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Games

B1. Mind games

Here is an introduction to mind games. This collection brings together games of reflection and observation, where one exercises, on one's own, logic, memory and a sense of wit.

Contents :

  1. Labyrinths
  2. Benford's law
  3. Crossword puzzle
  4. Mnemonics
  5. Palindromes
  6. Magic tricks



B1.1. Labyrinths

How to get out of a labyrinth for sure ?

  1. Introduction
  2. Tarry : in-depth search
  3. Tarry : course with overview
  4. Tarry : course without overview
  5. Tarry : shuttle between two crossroads of the labyrinth
  6. Oystein : search by concentric circles
  7. Distinction between crossroads and corridor
  8. Modeling a labyrinth and shortest path
  9. Sources
Picture Labyrinth1


B1.1.1. Introduction

Imagine any labyrinth made up of many crossroads and multiple corridors connecting these crossroads. How to get out of this labyrinth for sure ?
Figure 1 above gives an example of a simple labyrinth made up of 7 crossroads (numbered 1 to 7) including a dead end (crossroads 3), 10 corridors and 4 minimal loops ((55), (464), (2452) and (4564)).
The simplest rule for navigating a labyrinth, called the "hand rule", consists of crossing crossroads and corridors, always leaving the same hand (right or left) placed on the wall. This strategy allows you to never get lost in the labyrinth but does not guarantee finding the exit. Either the traveler possibly discovers one of the exits during his journey, or he automatically returns to his start crossroads.
Thus, on the example of Figure 1, with the right hand rule, a visitor lost at crossroads 5 will go indefinitely in circles in the loop (5245) by entering the corridor (52), and in the loop (5465) by entering the corridor (54).
The "rule of the hand" therefore only applies if the start crossroads corresponds to the entrance to the labyrinth, in which case the traveler is guaranteed to cross the labyrinth without getting lost along the way.

A general rule exists. It allows the lost traveler to definitely escape from the labyrinth when it has an outcome (entrance or exit) and, otherwise, to visit it completely before finding himself at his start crossroads. Two search strategies exist :
- In-depth search, when the traveler is completely lost in the labyrinth. Two different rules were published : rule of Charles-Pierre Trémaux in 1882 [LUC], and rule of Gaston Tarry in 1895 [TAR][TOU][ROS1] which is more general.
- Search by concentric circles (or breadth search), when the traveler knows that he is not too far from the entrance to the labyrinth (less than 3 or 4 crossroads for example). The rule was published by Oystein Ore in 1959 [OYS][WAL].
These three rules (Trémaux, Tarry and Oystein Ore) applie to any flat labyrinth, that is to say spread out on a relatively flat surface, as well as to any three-dimensional labyrinth that may include stairs and rooms with multiple floors.

We now describe Tarry's rule and Oystein's rule, then supplementing them with some general properties of labyrinths (Distinction between crossroads and corridor, and Modeling a labyrinth and shortest path).


B1.1.2. Tarry : in-depth search

When the traveler is completely lost in the labyrinth, the General Rule of the French mathematician Gaston Tarry is a double rule which is stated as follows :

At each crossroads of the labyrinth :
Rule no. 1 : Only retake the corridor of first visit to this crossroads as a last resort (Tarry's rule [TAR]).
Rule no. 2 : Never take a corridor twice in the same direction (remark from Pierre Tougne [TOU]).

Rule no. 1 allows you to escape the labyrinth with certainty. If the labyrinth does not have an outcome (entrance or exit), all crossroads are visited by traveling through each corridor exactly twice before returning to the start crossroads.
Rule no. 2 avoids wasting time by retracing paths already taken.

This double rule has many practical advantages :
- It is easy to remember.
- Subject to correctly marking certain particular corridors, it allows you to commute, at any time and without getting lost, between any finish crossroads and any start crossroads, and this without having to go through all the corridors already covered on the way there. This makes it possible in particular to return to a start crossroads (for example to pick up a person left there waiting) then to return to the finish crossroads (for example to bring the person back with you and continue the search together) [PET].
- It allows you to completely clean a labyrinth by passing through all the crossroads without exception.
- It allows you to successively cut each of the two sides of each corridor in a hedge labyrinth by passing through all the corridors twice without exception.


Proof of Tarry's general rule :

We will demonstrate that Tarry's rule allows us to visit all the crossroads of the labyrinth when it has no outcome (entrance or exit), which means that we certainly exit the labyrinth otherwise.
In the following, we consider that :
- A labyrinth is a set of crossroads whose exits are all connected to corridors ;
- Any two crossroads are connected by at least one continuous path passing through one or more corridors between crossroads (connected labyrinth) ;
- All corridors are two-way ;
- The start crossroads is a crossroads already visited by a fictitious arrival corridor.

Proposition no. 1 : Crossroads all completely visited (quick demonstration according to [TAR]) :
Since the corridors of the labyrinth are all two-way, any crossroads has as many exits as entrances. The traveler is therefore never stuck when visiting or revisiting a crossroads in the labyrinth. Consequently, if the labyrinth has no exit (entrance or exit) and if the rule no. 2 is scrupulously applied, the traveler will eventually stop at the start crossroads. At this moment, all the crossroads of the labyrinth are then necessarily completely visited, with all the corridors traveled exactly twice.

Proposition no. 2 : Crossroads all completely visited (complete demonstration by the Author of this Website) :
Since the corridors of the labyrinth are all two-way, any crossroads has as many exits as entrances.
Consequently (see Figure 4 below), the traveler who enters a crossroads via an arrival corridor (type R or T corridor) necessarily exits via a departure corridor not already taken in this direction (cf rule no. 2). This departure corridor can be the arrival corridor (with R rebound on the crossroads) or any other departure corridor (with T transit through the crossroads).
The first arrival at the crossroads (PV corridor) corresponds to the discovery of the crossroads via its corridor of first visit, followed by a departure via any corridor.
The last arrival at the crossroads (DV corridor) corresponds to the last visit to the crossroads with a return in the opposite direction to the corridor of first visit (cf rule no. 1).
The traveler is therefore never stuck when he visits or revisits a crossroads in the labyrinth.
Consequently, if the labyrinth has no outcome (entrance or exit) and if rule no. 2 is scrupulously applied, the traveler will eventually stop at the start crossroads after having visited a certain number of crossroads.
Any crossroads visited for the first time is via a corridor traveled from another crossroads necessarily visited for the first time. Consequently, any crossroads visited at least once is on a tree whose trunk is the start crossroads and whose branches are the first visit corridors of each crossroads (see example in Figure 5 below).
Suppose that there is on this tree a crossroads whose first visit corridor is never taken in the opposite direction. In this case, the upstream crossroads located on the tree just before this downstream crossroads finds itself in the same situation (see rule no. 1). Step by step, the start crossroads located at the base of the tree (first crossroads visited) also finds itself in the same situation, which is contradictory with the fact that the traveler always ends up returning to the start crossroads. Consequently, if the rule no. 1 has been scrupulously applied at each crossroads, all crossroads in the tree are completely visited.
Furthermore, the labyrinth being connected, any crossroads (C) not already visited and connected to a crossroads of the tree at the distance of a corridor will therefore visited, which extends the tree and makes crossroads C completely visited. Step by step, all the crossroads of the labyrinth will therefore be completely visited, with all the corridors of the labyrinth traveled exactly twice (once in the arrival direction and once in the starting direction).

On a practical level, the completely visited crossroads of the labyrinth are therefore successively visited in the form of downstream-upstream fallbacks which necessarily end at the start crossroads. On the example of Figure 2 above, if crossroads 7 is not an exit but a simple dead end, the path is as follows :
- The route between the departure from crossroads 1 and the arrival at crossroads 7 is given by the succession of corridors (12)(24)(45)(52)(25)(55)(56)(64)(43)(34)(46)(67). See following paragraph.
- The route to then return to the crossroads 1 is given by the succession of corridors (76)(64)(46)(65)(55)(54)(42)(21).
The fallback corridors are (34) then (76) then (65) then the series (54)(42)(21)), and correspond to the branches of the tree of the corridors of first visit to each crossroads (see Figure 5 below).

Conclusion :
The traveler therefore visits all the crossroads of the labyrinth when it has no outcome (entrance or exit), which means that one will certainly exit the labyrinth otherwise.
picture Labyrinth2


B1.1.3. Tarry : course with overview

In the fun case where the traveler has an overview of the labyrinth, the traveler must analyze each crossroads and its adjoining corridors as follows :
A. Just before entering a crossroads, the traveler must mark the Corridor of first Visit to the crossroads (PV) which is the corridor through which the visitor enters the crossroads for the first time. To do this, he creates a PV mark at the right end of the arrival corridor.
B. Just before leaving the crossroads, the traveler must mark the Last departure corridor from the crossroads (D) which is the most recent corridor through which the visitor exits the crossroads. To do this, he creates a D mark at the right entrance to the departure corridor.

Let's see this course on the example of Figure 1.
The crossroads are marked by the numbers 1, 2... 7 where 1 is the start crossroads of the lost traveler and 7 the only outcome of the labyrinth (entrance and exit). The route of a corridor is noted by the number of the start crossroads followed by the number of the end crossroads, for example (24).
Initially, the traveler finds himself lost at crossroads 1 and seeks to reach the exit of the labyrinth (crossroads 7).

Figure 2 above shows a possible course accompanied by the marks created at the end of each arrival corridor (PV or no mark) and at the entrance to each departure corridor (D).
In the case of a dead end (single-exit crossroads), the PV and D marks are not useful since the traveler will never return to this crossroads (see crossroads 3 in Figure 2).
Let's start from the crossroads (1) and take the only possible corridor (12).
At crossroads 2, choose one of the four unexplored corridors, for example (24). At crossroads 4, let's choose, for example, corridor (45). At crossroads 5, let's choose for example corridor (52). Until now, it has been easy to apply the general rule because there was, at each crossroads visited, an unexplored corridor and each crossroads was visited for the first time.
At crossroads 2 (already visited), we cannot take corridor (21) which is the corridor of first visit to the crossroads (cf rule no. 1), nor corridor (24) already taken in this direction (cf rule no. 2). The only option left is to turn back via the corridor (25).
At crossroads 5 (already visited), let's choose for example the right corridor which is in fact a loop (55). Back at crossroads 5, let's choose for example the corridor (56). At crossroads 6, let's choose for example the corridor (64).
At crossroads 6, let's choose, for example, corridor (64).
At crossroads 4 (already visited), by application of rules no. 1 and 2, we can only take one of the two unexplored corridors (43) or (46), or turn back via the other corridor (46).
The first tactic is called "Crazy Ariadne", the second "Sage Ariadne or Trémaux Algorithm". These two tactics are equivalent if we seek to explore the entire labyrinth. The "Crazy Ariadne" tactic is, however, preferable if we are looking for a way out. Let's choose this tactic and take the corridor (43).
At crossroads 3 (dead end), we must turn back via corridor (34).
At crossroads 4 (already visited), let's choose for example the unexplored corridor (46) then, arriving at crossroads 6, the corridor (67) leading to exit 7.
In total, the course between start 1 and exit 7 of the labyrinth is given by the succession of corridors (12)(24)(45)(52)(25)(55)(56)(64)(43)(34)(46)(67).
The corridors of first visit to each crossroads are indicated in bold font.


B1.1.4. Tarry : course without overview

In the real case where the traveler does not have an overview of the labyrinth, the traveler must stop at each crossroads and go completely around it in order to analyze all the adjoining corridors as follows :
A. Just before entering a cossroads, the traveler must temporarily mark the arrival corridor as the assumed corridor of First Visit to the crossroads. To do this, it creates a P mark at the right end of the arrival corridor. This mark also allows you to go completely around the crossroads, returning calmly to the P mark.
   - If the assumption is true (crossroads having no PV mark), the traveler must change the P mark to PV mark in order to be able to apply rule no. 1 during a next visit to the crossroads.
   - If the assumption is false (crossroads already having a PV mark), the traveler must cancel the P mark by crossing it out ("P crossed out") in order to return to initial conditions during a next visit to the crossroads.
B. Just before leaving the crossroads, the traveler must mark two particular departure corridors at the right entrance to each corridor. He must first cancel the D mark of the last corridor explored by crossing it out ("D crossed out"). He must then create a D mark on the corridor he is going to take. The "crossed out D" mark is only useful if the traveler plans to commute through the labyrint between an finish crossroads and a start crossroads. Note that, although crossed out, this mark remains a mark of a corridor already explored, therefore eligible for rule no. 2.
Figure 3 above shows the same course as that of Figure 2, accompanied by the marks created at the end of each arrival corridor (P, then PV or P crossed out) and at the entrance to each departure corridor (D crossed out if D exists, then D).
In the case of a dead end (single-exit crossroads), the P, PV and D marks are not useful since the traveler will never return to this crossroads (see crossroads 3 in Figure 3).

In the case where the traveler has nothing to mark the walls of the corridors but where he has small stones (like Tom Thumb), then the marks can be advantageously replaced as follows.
But be careful not to confuse the right entrance and left entrance to each corridor when going around the crossroads !

MarkStone management
PJust before entering a crossroads, place 1 stone at the right end of the arrival corridor.
PVAfter a complete tour of the crossroads without discovering a pair of stones at the left entrance to a corridor, add 1 stone to the stone placed.
P crossed outDuring the complete tour of the crossroads with discovery of a pair of stones at the left entrance to a corridor, finish the tour and pick up the stone placed.
D crossed outDuring the complete tour of the crossroads with discovery of a pair of stones at the right entrance to a corridor, pick up 1 stone out of the 2.
DJust before leaving the crossroads, place 2 stones at the right entrance to the departure corridor.


B1.1.5. Tarry : shuttle between two crossroads of the labyrinth

If the traveler has made sure to keep only one D mark at each crossroads (see point B above), he can then commute, at any time and without getting lost, between two crossroads of the labyrinth as following :
- Returning to a start crossroads (for example to pick up a person left there waiting) then becomes possible and easy. At each crossroads, simply take the corridor marked PV at the left entrance to the corridor in the opposite direction, without generating new marks [PET]. The return path from an finish crossroads to any start crossroads in fact constitutes a tree whose trunk is this start crossroads and whose branches are the corridors marked PV (see Figure 5 below).
Proof : Any crossroads visited the first time is via a corridor traveled from another crossroads necessarily visited the first time. Consequently, any crossroads visited for the first time is on a tree whose trunk is the start crossroads and whose branches are the corridors of first visit to each crossroads.
This tree is called "tree of corridors of first visit to each crossroads" or "tree of crossroads visited the first time".
- Then returning to the finish crossroads (for example to bring the person back with you and continue the search together) also becomes possible and easy. At each crossroads, simply take the corridor marked D at the right entrance to the corridor in the same direction, without generating new marks [PET]. The return path from a start crossroads to any finish crossroads also constitutes a tree whose trunk is this finish crossroads and whose branches are the corridors marked D (see Figure 6 below).
Proof : Any crossroads visited the last time is via a corridor traveled from another crossroads necessarily visited the last time. Consequently, any crossroads visited last time is on a tree whose trunk is the finish crossroads and whose branches are the last departure corridors from each crossroads.
This tree is called "tree of last departure corridors from each crossroads" or "tree of crossroads visited last time".

picture Labyrinth3


B1.1.6. Oystein : search by concentric circles

When the lost traveler knows that he is not too far from the entrance to the labyrinth (less than 2 or 3 crossroads for example), the general rule of the Norwegian mathematician Oystein Ore allows this entrance to be reached by concentric circles from the start crossroads, without the need to explore the labyrinth in depth.
The general rule is then the following [WAL] :

1. From the start crossroads, travel the corridors leading to a distance of 1 crossroads one by one, marking with a line each of the two ends of each corridor traveled.
2. Block both ends of the corridor by changing the marks to a cross in the following four cases :
   A. the corridor marked with a line is a dead end (corridor (43) in step 3 below) ;
   B. the corridor marked with a line is a loop connecting two exits from the same crossroads (corridor (55) in step 3 below) ;
   C. the corridor marked with a line leads to a crossroads already visited (corridors (45), (46) and (56) in step 3 below) ;
   D. the corridor leads to a crossroads from which all exits are blocked (corridor (25) in step 4 below).
3. Return to the start crossroads following the marks.
4. Repeat the operation by traveling all the non-condemned corridors leading to a distance of 2 crossroads, following the marks, and adding a line at each of the two ends of each corridor during its outward journey.
   E. The outward and return marks tracking is simple : their number decreases by 1 at each crossroads crossed on the way out and increases by 1 at each crossroads crossed on the way back.
5. Return to the start crossroads following the marks.
6. Repeat the operation as many times as necessary, going at a distance of 3 crossroads, then 4, etc.


Proof of Oystein's general rule :
(Complete demonstration by the Author of this Website)

Oystein's general rule is to travel the labyrinth by gradually expanding the search in concentric circles passing through the crossroads.
The level 0 circle (denoted C0) is the start crossroads.
The circle of level n (denoted Cn) whatever n > 0, passes through all the crossroads a crossroads away from the circle Cn - 1.
An outward corridor is a corridor connecting a crossroads of the circle Cm to a crossroads of the circle Cm + 1 whatever m ≥ 0. It is always traversed by marking it with an additional line at each end.
A return corridor is a corridor connecting a crossroads of the circle Cm + 1 to a crossroads of the circle Cm whatever m ≥ 0. It is always traveled without generating additional marks.
Having established these definitions, exploring a new circle Cn + 1 for given n consists of visiting at least once all the crossroads of the circle Cn + 1 using the following strategy :
- Reach each crossroads of the Cn circle via the route of outward and/or return corridors following the marks (see law E above), then travel through all the new outward corridors (unmarked and not condemned) connecting this crossroads to the crossroads of the circle Cn + 1.
- Return to the start crossroads via the return corridor route following the marks (see law E above).
Moreover :
- Condemning any corridor connecting two crossroads already visited (see law C above) amounts to removing any loop internal to the labyrinth passing through at least two crossroads (loops (4524), (464) and (5645) in step 3 below), which transforms the labyrinth into a tree whose trunk is the start crossroads and whose foliage is all the uncondemned corridors.
- Condemning any dead end (see law A above) amounts to removing any blind corridor connected to the crossroads (corridor (43) in step 3 below), which simplifies the tree by removing the terminale branches.
- Condemning any loop connecting two exits from the same crossroads (see law B above) amounts to removing any internal loop at the crossroads (corridor (55) in step 3 below), which simplifies the tree by removing the branches folded on themselves.
- Condemning any corridor leading to a crossroads where all exits are condemned (see law D above) amounts to simplifying the tree even further by removing the "dead" branches (corridor (25) in step 4 above). below).
The labyrinth finally transforms into a tree whose foliage gradually passes through all the crossroads not yet visited, including inevitably through the exit crossroads from the labyrinth.


In the fun case where the traveler has an overview of the labyrinth, the general rule applies without difficulty.
Figure 7 below shows a possible course from the start crossroads of the labyrinth in Figure 1, accompanied by the marks created on each corridor traveled (lines or crosses).
The succession of corridors traveled is as follows. Condemned corridors are indicated in bold font.
- Remote exploration of 1 crossroads : (12)(21)
- Remote exploration of 2 crossroads : (12)(24)(42)(25)(52)(21)
- Remote exploration of 3 crossroads : (12)(24)(45)(54)(46)(64)(46)(64)(43)(34)(42)(25)(55)(56)(65)(52)(21)
- Remote exploration of 4 crossroads : (12)(25)(52)(24)(46)(67)
The exit from the labyrinth (also corresponding to the entrance) is found after exploration by concentric circles at a distance of 4 crossroads.

In the real case where the traveler does not have an overview of the labyrinth, the traveler must stop at each crossroads, take a complete tour in order to analyze all the adjoining corridors, then take the return corridor in possibly condemning him. The traveler can then take the wrong corridor when a crossroads has several exits marked with a single line. For example, for crossroads 5 in step 3 below, when taking the return corridor (54), the traveler may mistakenly take the corridor (52) traveled in step 2.
The general rule must therefore be supplemented as follows :
4 bis - Just before entering a crossroads via a new corridor (unmarked and not condemned), when marking the corridor end with a simple line, the traveler must add a different mark (for example P). This particular mark will allow you to calmly take the complete tour of the crossroads and take the return corridor without mistake.

image Labyrinthe4


B1.1.7. Distinction between crossroads and corridor

A labyrinth described in the form of a graph does not present ambiguity between crossroads and corridors, a crossroads being a node of the graph and a corridor an arc connecting two nodes.
But in reality, a crossroads or a corridor is a navigation area that can be complex to analyze at the topological level : more or less vast, more or less narrow area, with the possible presence of niches, shallow dead ends, protusions or small islets. In a crossroads already visited, the traveler may, for example, not find the exact location of an exit or worse, see new corridors appear within the same crossroads. When traveling (in the opposite direction) through a corridor already traveled, the traveler can also, for example, see new crossroads appear within the same corridor.

To avoid any ambiguity, the vocabulary must be rigorously defined as follows :
- A Labyrinth is a set of Crossroads whose Exits are all connected to Corridors.
- A Crossroads is a Navigation area with 1 Exit, 3 Exits, or more than 3 Exits (see example in Figure 8 below). The "1 Exit" case corresponds to a dead end, which is the end of a blind Corridor (crossroads 3 in Figure 1 above), or any single-corridor crossroads that may be a start crossroads (crossroads 1 in Figure 1) or an outcome from the labyrinth (crossroads 7 in Figure 1).
- A Corridor connects two Crossroads by a single Section or by a succession of several consecutive Sections (see example in Figure 8). A Corridor can form a loop when it connects two Exits from the same Crossroads (case of Figure 8).
- A Section is a Navigation area with exactly 2 Exits (see example in Figure 8). A Section is generally empty (without islets) and narrow. It can also be presented in reduced form in length, such as a doorway between two Crossroads.
- A Navigation area is a connected space (in one piece) as large as possible, having all its points intervisible or quasi-intervisible, and delimited by one or more Exits. The space may include niches, shallow dead ends, protusions and small islets. Figure 8 below gives an example of three Navigation areas : 1. a Crossroads (indicated in bold font) including five Exits (S1, S2, S3, S4, S5), a niche (N), a shallow dead end (C), a protusion (A) and two small islets (I1, I2)) ; 2. an empty Section (S3, S) ; 3. a Section (S, S4) with a small islet ; these two Sections forming a Corridor between the S3 and S4 Exits of the Crossroads.
- An Exit is the limit of a Crossroads or a Section, beyond which the intervisibility criterion for a Navigation Area is no longer respected.

image Labyrinthe5


B1.1.8. Modeling a labyrinth and shortest path :

When we have an overview of a labyrinth, it can be modeled by an incidence matrix (M) whose rows and columns are the crossroads numbers and each element of the matrix indicates the number of corridors (0, 1, 2, etc.) connecting one crossroads to another [WAL]. Figure 10 above shows an example of a labyrinth and its corresponding incidence matrix.
The incidence matrix also makes it possible to model a labyrinth with one-way corridors [WAL] provided that these corridors do not form a loop connecting two exits from the same crossroads or a loop connecting two crossroads.

For study purposes, any labyrinth can be simplified as follows :
1. Any dead end can be removed by considering that it is integrated (as a shallow dead end) into the crossroads leading to it.
2. Any loop connecting two exits from the same crossroads can be removed by considering that it is integrated (as a small islet) into the crossroads.
3. Any loop connecting two crossroads can be reduced to a single corridor between these crossroads by considering that it is integrated (as a small islet) into this corridor.
4. Any crossroads whose number of corridors is reduced to 2 by one or more of the preceding simplifications can be removed by directly connecting the two corridors.
5. Any crossroads with n corridors such that n > 3 can be replaced by a ring formed by n crossroads with 3 corridors each [STE] on condition of agreeing to violate rule no. 2 in the modified crossroads in order to be able to travel the ring between any two crossroads (see Figure 9 above).
If the traveler knows how to navigate the modified labyrinth, then he or she can also find a path through the original labyrinth by restoring the original crossroads and corridors.
Figure 10 shows the labyrinth equivalent to that of Figure 1 by applying simplifications 1 to 4.

The incidence matrix of a labyrinth makes it possible to find the number of corridors of the shortest path connecting one crossroads to another [WAL].
By multiplying the matrix M by itself (see Figure 10), we obtain a new matrix (M2) whose elements indicate the number of different ways of going from one crossroads to another via a path made up of 2 corridors. By repeating the operation n times, we obtain a matrix (Mn) whose elements indicate the number of different ways of going from one crossroads to another by a path made up of n corridors [WAL].
To find the shortest path connecting one crossroads to another, it is then sufficient to raise the matrix M to a power such that the element corresponding to the connection between these two crossroads becomes non-zero. The power then gives the number of corridors of the shortest path [WAL].
Figure 10 above shows that the shortest path to go from crossroads 1 to crossroads 7 is obtained for n = 4 with 2 possible paths made up of n = 4 corridors.


B1.1.9. Sources relating to labyrinth

[LUC] Edouard Lucas, Le jeu des labyrinthes, in Récréations mathématiques, tome I (2ème édition, Paris, 1882), chapitre 3, pp. 41-55.
[OYS] Oystein Ore, An excursion into labyrinths, in The Mathematics Teacher, pp. 367-370, Vol. 52, N 5, May 1959.
[PET] Régis Petit, Labyrinthes et arbres, article de la revue "CANAL.N7", journal de l'association des ingénieurs de l'I.E.T.- E.N.S.E.E.I.H, N 33 de septembre 1994.
[ROS1] Pierre Rosensthiel, Les mots du labyrinthe, Revue CoEvoluion. N 11. Hiver 1983.
[ROS2] Pierre Rosensthiel, Labyrintologie mathématique, in Mathématiques et sciences humaines, tome 33 (1971), p.5-32.
[STE] Ian Stewart, Algorithmes labyrinthiques, article de la revue Pour la science, rubrique Visions mathématiques, N 162 d'avril 1991.
[TAR] Gaston Tarry, Le problème des labyrinthes, Nouvelles annales de mathématiques 3e série, tome 14 (1895), p. 187-190.
[TOU] Pierre Tougne, Comment explorer un labyrinthe ?, article de la revue Pour la science, rubrique Jeux mathématiques, N 60 d'octobre 1982, réactualisé dans Pierre Tougne, L'exploration d'un labyrinthe, Dossier Pour la science, Avril/Juin 2008.
[WAL] Jearl Walker, Comment traverser un labyrinthe sans se perdre ni tourner en rond, article de la revue Pour la science, rubrique Expériences d'amateur, février 1987.



B1.2. Benford's law

Benford's law, or Newcomb-Benford law, or law of abnormal numbers, or law of the first significant digit, shows that in everyday life, the first significant digit of numbers is not equiprobable : the number 1 is more frequent than 2, itself more frequent than 3, etc.
This curiosity is observed in many fields such as the human and social sciences, tables of numerical values, genetics, construction, economics (exchange rates) or even in the street numbers in one's address book [WIK1].
Open the page of a newspaper at random, note all the numbers you find there. Then look at the first significant digit of each number. It is the leftmost digit, which is not zero. Do not take into account either the sign or the place of the decimal point : for example, the first significant digit of the numbers 0.038   3.14159 and -32 is 3.
To your great surprise, you will notice that the digit 1 appears for almost a third of the numbers, the digit 2 approximately once in 6, and that the frequency of appearance decreases until the digit 9 (less than once in 20) [ROU].

  1. Definition
  2. Application areas
  3. Explanation
  4. Case of the digits following the first
  5. Case of the sequence of natural integers
  6. Case of numerical sequences
  7. Sources
picture Benford's law     picture Benford's law


B1.2.1. Definition :
Benford's law gives the theoretical value (f) of the frequency of appearance of the first significant digit (c) of a measurement result expressed in a given base (b) [WIK1] : fc = logb(1 + 1/c)
We verify that the sum of the frequencies fc is worth : ∑i = 1, (b-1) [logb(1 + 1/i)] = logb(b) = 1
In the decimal system (base b = 10), the law is therefore : fc = log10(1 + 1/c)
For example, the Benfordian probability that a base 10 number begins with the digit c = 1 is as follows : f1 = log10(2) = 30.1 %
The table above gives the frequency fc in percentage for each value of the first digit c between 1 and 9.
Benford's law remains invariant by changing the number base and also by multiplication by a constant, particularly when changing units.

B1.2.2. Application areas :
Benford's law applies all the better when the series of numbers is "rich", with numbers of varied origins (case of a good mixture of any series) and/or relatively well spread over a range covering several orders of magnitude (sizes of cities for example) [ROU][DEL2].
Thus, the house numbers found in an address directory satisfy Benford's law quite well [DEL1]. If a street has 50 numbers, then more than a fifth of the numbers start with a 1 (because of 10, 11, 12... 19). If it has 20 or 200, more than half of the numbers start with a 1. It is therefore normal to find on average more often numbers starting with a 1 than with 9 (and more generally with the digit c than with c + 1) [LED1].
Benford's law does not apply for various cases, including the following [WIK1][DEL1] :
- Numbers drawn at random (the digits c will then all be equally probable).
- Numbers whose first digit is imposed, for example telephone numbers or vehicle registration numbers.
- Restricted scale of possible values, for example the height of individuals in meters (almost all measurements starting with the digit 1) or the selling price of a particular model of new car (the price varies little from one dealer to another) to another).

Benford's law is mainly used to detect tax, financial, accounting and scientific fraud. The principle is as follows : if they regularly extend over several orders of magnitude, the numbers appearing in accounts or statistics must, unless there are special reasons, verify Benford's law. If these are invented numbers, then the forger must have wanted to create as many starting with 1 as with 2, 3, etc., which will contradict Benford's law [DEL2].
In a document containing N numbers, if Nc is the number of times the first significant digit is c, if fc is the frequency of appearance of the digit c according to Benford's law, then we define a test statistic T as follows [AMQ][WIK2] :
T = ∑c = 1, 9 [ (Nc - N fc)2 / (N fc) ] = N ∑c = 1, 9 [ ((Nc/N) - fc)2 / fc ]
For large N, the statistic T then behaves like a variable of the law of X2 at v = (9 - 1) degrees of freedom [AMQ].
By comparing T with the quantile Q of order 95 % of the X2 law with v = 8 degrees of freedom [WIK2], we can conclude that the series of numbers is most certainly faked in the case where T > Q

Benford's law is also used to detect the existence of hidden messages in images (steganography). Two main methods exist [ATO] :
The first method examines the lead digit distribution of the raw contents of the bytes of a suspect image.
The second method examines the distribution of lead digits of quantised discrete cosine transform (DCT) coefficients of the JPEG encoding.


B1.2.3. Explanation :
Benford's law remains imperfectly explained to this day [DEL1]. The best explanation seems to be this :
We demonstrate mathematically that the sequence of natural integers (1, 2, 3... n) satisfies a "weak" form of Benford's law (in the sense of Cesàro's iterated averages) [DEL1].
This is why it seems legitimate, when the data set is "rich" (see Application areas above), to find statistically in everyday life, series of numbers whose first significant digit is not equiprobable and approximately follows Benford's law.

B1.2.4. Case of the digits following the first :
1. Case of a block of digits in first position [WIK1] : The Benfordian probability that a number in base b begins with the digit block (cde) is as follows : fcde = logb(1 + 1/cde)
For example, for the block cde = "314" in base 10, we have : f314 = log10(1 + 1/314) = 0.138 %
Another example, for the block cde = "10" in base 3 (i.e. cde = 3 in base 10), we have : fcde = log3(1 + 1/3) = 26.2 %
2. Case of a digit in position k [WIK1] : The Benfordian probability that a digit (c) is at a given position (k > 1) in a number in base b is as follows : fc = ∑i = bk-2, (bk-1 - 1) [logb(1 + 1/(i b + c))]
For example, the Benfordian probability in base 10 that the digit c = 0 appears in the second position (k = 2) is : log10(1 + 1/10) + log10(1 + 1/20) + ... + log10(1 + 1/90) = 12.0 %.
This law quickly approaches a uniform law with a value of 10 % for each of the ten digits (see Table above).

B1.2.5. Case of the sequence of natural integers :

For the sequence of natural integers (1, 2, 3... n), the digits c in base b are only equally distributed (of frequency M = 1/(b - 1))) when n is exactly (b - 1), (b2 - 1)... (bp - 1) for p integer ≥ 1, which almost never happens [CHA].

Otherwise, the frequencies of the first digit c in base b constantly oscillate between two extreme values Msup and Minf taken respectively at nsup and ninf, such that [WIK1][CHA] :
nsup = (c + 1) bp - 1 - 1
ninf = c bp - 1
Msup = ( (bp - 1)/(b - 1) ) / nsup   which tends to   Msupapp = b/( (c + 1)(b - 1) )   for p = +∞
Minf = ( (bp - 1)/(b - 1) ) / ninf   which tends to   Minfapp = 1/( c (b - 1) )   for p = +∞
We have the relation :   Minf ≤ Minfapp ≤ M ≤ Msupapp < Msup   since we always have :   1 ≤ c ≤ b - 1   and   b > 1

In base 10 and for p = 1, the value of the couple (Msup, Minf) is :
    (1, 1/9) for the digit 1, obtained in (nsup, ninf) = (1, 9),
    (1/5, 1/49) for the digit 5, obtained in (nsup, ninf) = (5, 49),
    (1/9, 1/89) for the digit 9, obtained in (nsup, ninf) = (9, 89).
In base 10 and for p = 2, the value of the couple (Msup, Minf) is :
    (11/19, 11/99) for the digit 1, obtained in (nsup, ninf) = (19, 99),
    (11/59, 11/499) for the digit 5, obtained in (nsup, ninf) = (59, 499),
    (11/99, 11/899) for the digit 9, obtained in (nsup, ninf) = (99, 899).
In base 10 and for p = +∞, the value of the couple (Msupapp, Minfapp) is :
    (5/9, 1/9) for the digit 1,
    (5/27, 1/45) for the digit 5,
    (1/9, 1/81) for the digit 9.
For example, the graph above shows the frequency curve of the first digit 1 (in red) and that of the first digit 9 (in blue) for integers from 1 to 10,000, in logarithmic scale [WIK1].

The sequence fc(n) therefore does not converge and oscillates indefinitely between two extreme values. To smooth these oscillations [DEL1], we take the average sc(n) = (1/n) ∑k = 1, n [fc(k)], called Cesàro average. The new sequence sc(n) still does not converge but varies in a narrower interval.
By repeating this averaging process (tc(n) = (1/n) ∑k = 1, n [sc(k)]), we obtain successive sequences (tc(n), uc(n), etc.) which vary in increasingly narrow intervals and B. Flehinger demonstrated in 1966 that the interval that we obtain by continuing these calculations of averages of averages approaches, to infinity, the expected value of the Benford's law, i.e. logb(1 + 1/c)
Thus, the frequency of integers starting with the digit c satisfies a "weak" form of Benford's law (in the sense of Cesàro's iterated averages), each frequency converging towards the value logb(1 + 1/c)
This convergence in the Cesàro sense makes it possible to converge sequences which were divergent. Known example, the sequence "01010101..." converges to 1/2 in the Cesàro sense.

B1.2.6. Case of numerical sequences :
Certain remarkable numerical sequences satisfy Benford's law at infinity, that is to say that the proportion of the terms of the sequence up to n, the first digit of which is c, tends towards the value log10(1 + 1 /c) when n tends to infinity.
This is the case of the sequences 2n, nn and (n!), as well as the coefficients of Newton's binomial [DEL1].
It is the same for any sequence rn where r is a positive real such that log10(r) is not a rational number (that is to say a ratio of two integers) [DEL1].
It is also the same for any sequence defined by a recurrence relation of type : u(n) = a1 u(n - 1) + a2 u(n - 2) + ... + ap u(n - p), in particular for the Fibonacci sequence (defined by : u(0) = u(1) = 1 and u(n) = u(n - 1) + u(n - 2)) [DEL1].

B1.2.7. Sources relating to Benford's law

[AMQ] Association Mathématique du Québec, La loi de Newcomb-Benford ou la loi du premier chiffre significatif.
[ATO] P. Andriotis, T. Tryfonas, G. Oikonomou, T. Spyridopoulos, On Two Different Methods for Steganography Detection in JPEG Images with Benford's Law, NATO Spie conference 2013.
[CHA] Jean-Marie Champeau, Les illusions - La loi de Benford.
[DEL1] Jean-Paul Delahaye, L'étonnante loi de Benford, article de la revue Pour la science, rubrique Logique et calcul, N 351 de janvier 2007.
[DEL2] Jean-Paul Delahaye, Une explication pour la loi de Benford, article de la revue Pour la science, rubrique Logique et calcul, N 489 de juillet 2018.
[ROU] Thierry de la Rue, Gaëlle Chagny, L'incroyable statistique des premiers chiffres, Université de Rouen.
[WIK1] Wikipedia, Loi de Benford.
[WIK2] Wikipedia, Test du X2.



B1.3. Crossword puzzles

Listed below are the largest crossword puzzles designed without any black squares ("perfect" crossword puzzles)), known in French, English, Italian, Spanish, Latin, Serbian, Croatian,Hungarian, Hebrew, German.
Some crossword puzzles are classic (rectangular, or square with different words horizontally and vertically, sometimes called "asymmetric grids"), others are symmetric (square with repetition of the same words horizontally and vertically, called "magic letter squares").
In both cases, the most "beautiful" crossword puzzles are those for which all the words are expressed in the same language, excluding proper nouns, and are natively written without any separator (space, period, hyphen, apostrophe, etc.). They are indicated by the label ***

The records for the largest perfect crossword puzzles in 2024 are as follows :
1. In French :
     * Claude Coutanceau (classic 9x9 crossword puzzle)
     *** Jean-Charles Meyrignac (classic 9x8 crossword puzzle)
     * Michel Laclos (symmetrical 10x10 crossword puzzle)
     * Régis Petit (2 symmetrical 10x10 crossword puzzles)
     *** Christophe Lecoutre and Sébastien Tabary (symmetrical 9x9 crossword puzzle)
     *** Laurent Bartholdi (2 symmetrical 9x9 crossword puzzles)
     *** Brice Allenbrand (49 symmetrical 9x9 crossword puzzles)
2. In English :
     * Jeff Grant (symmetrical 12x12 crossword puzzle)
     * Jeff Grant (symmetrical 11x11 crossword puzzle)
     * Rex Gooch (2 symmetrical 11x11 crossword puzzles)
     *** Matevz Kovacic (symmetrical 10x10 crossword puzzle)
3. In Italian :
     *** Author unknown (symmetrical 8x8 crossword puzzle)
4. In Spanish :
     *** Author unknown (symmetrical 8x8 crossword puzzle)
5. In Latin :
     *** Eric Tentarelli (2 symmetrical 11x11 crossword puzzles)
6. In Serbian :
     * Boris Nazanski (symmetrical 10x10 crossword puzzle)
     * Zivota Stankovic (symmetrical 10x10 crossword puzzle)
7. In Croatian :
     * Milutin Tepsic (symmetrical 11x11 crossword puzzle)
     * Zarka Dokica (symmetrical 11x11 crossword puzzle)
8. In Hungarian :
     * Author unknown (classic 9x9 crossword puzzle)
9. In Hebrew :
     * Author unknown (classic 10x10 crossword puzzle)
10. In German :
     *** Claude (17 symmetrical 8x8 crossword puzzles)
11. In other languages :
Other perfect crossword puzzles are available in otherlanguages (*) but with modest dimensions (8-By-8 and smaller). See [CPT Collection].
(*) Arabic, Armenian, Belarusian, Bulgarian, Chinese, Czech, Danish, Dutch, German, Greek, Hindi, Kazakh, Korean, Lithuanian, Macedonian, Persian (Farsi), Polish, Portuguese, Romanian, Russian, Slovenian, Swedish, Turkish, Ukrainian.

Acknowledgments : The author thanks Jean-Charles Meyrignac for his advice and the provision of some of the sources.
Help us : If you know of any other crossword puzzles that are 8x8 or larger, please Contact us.


B1.3.1. French crossword puzzles :


Classic crossword puzzles (one 9-By-9 and one 9-By-8 crossword puzzles) :

picture Crossword puzzle - Claude Coutanceau picture Crossword puzzle - Jean-Charles Meyrignac


* Figure 1 : 9-By-9 crossword puzzle created in 2010 by Claude Coutanceau [DRI][WIK, Mots croisés].
Horizontally :
  REABRASES : du verbe réabraser (abraser à nouveau)
  ENCRENENT : du verbe encréner (faire des créneaux)
  OCTOCORDE : instrument de musique constitué de 8 cordes à 8 notes conjointes
  CHICORIUM :
         1. Nom latin utilisé dans les textes botaniques et médicaux pour désigner la chicorée.
         2. Erreur d'orthographe en français pour le nom Cichorium, genre botanique relatif aux chicorées. Cette faute se trouve souvent dans les articles culinaires, voire scientifiques.
         3. Nom d'une entreprise basée à Pulborough en Angleterre.
  RAVAUDERA : du verbe ravauder (raccommoder en couture)
  EPARTIRAS : du verbe épartir (épandre)
  RENIERONS : du verbe renier (désavouer)
  ALTERANTE : de l'adjectif altérant (qui altère)
  SASSASSES : du verbe sasser (tamiser)
Vertically :
  REOCRERAS : du verbe réocrer (ocrer à nouveau)
  ENCHAPELA : du verbe enchapeler (coiffer)
  ACTIVANTS : de l'adjectif activant (qui active)
  BROCARIES :
         1. Ancien écart ou hameau de la commune de Varennes en Dordogne [GOU]
         2. Du verbe catalan brocar (deuxième personne du singulier du conditionnel) signifiant percer
  RECOUTERA : du verbe recoûter (coûter à nouveau)
  ANORDIRAS : du verbe anordir (tourner au nord)
  SERIERONS : du verbe sérier (classer)
  ENDURANTE : de l'adjectif endurant (qui endure)
  STEMASSES : du verbe stemer ou stemmer (faire un stem au ski)

*** Figure 2 : 9-By-8 crossword puzzle created in 2004 by Jean-Charles Meyrignac [ECK, A near-perfect French 9-By-8 word rectangle][WIK, Mots croisés].
Horizontally:
  DECROCHES : de l'adjectif décroché
  ECOEURANT : de l'adjectif écoeurant
  RONFLANTE : de l'adjectif ronflant
  ATTRISTER : du verbe attrister
  PARAPHERA : du verbe parapher
  EMACIERAS : du verbe émacier
  REITERAIS : du verbe réitérer
  ASSENASSE : du verbe asséner
Vertically:
  DERAPERA : du verbe déraper
  ECOTAMES : du verbe écôter (enlever la côte des feuilles de certains légumes)
  CONTRAIS : du verbe contrer
  REFRACTE : du verbe réfracter
  OULIPIEN : de l'adjectif oulipien (relatif à l'oeuvre littéraire Oulipo)
  CRASHERA : du verbe crasher
  HANTERAS : du verbe hanter
  ENTERAIS : du verbe enter
  STERASSE : du verbe stérer


Word squares (3 10-By-10 and 54 9-By-9 word squares, partial display) :

picture Crossword puzzle - Michel Laclos picture Crossword puzzle 1 - Regis Petit picture Crossword puzzle 2 - Regis Petit
picture Crossword puzzle - Roger La Ferte picture Crossword puzzle - Guy Brouty picture Crossword puzzle - Christophe Lecoutre and Sebastien Tabary picture Crossword puzzle - Laurent Bartholdi
image Mots croises - Grille de Brice Allenbrand image Mots croises - Grille de Brice Allenbrand image Mots croises - Grille de Brice Allenbrand image Mots croises - Grille de Brice Allenbrand
image Mots croises - Grille de Brice Allenbrand image Mots croises - Grille de Brice Allenbrand image Mots croises - Grille de Brice Allenbrand image Mots croises - Grille de Brice Allenbrand
image Mots croises - Grille de Brice Allenbrand image Mots croises - Grille de Brice Allenbrand image Mots croises - Grille de Brice Allenbrand image Mots croises - Grille de Brice Allenbrand
image Mots croises - Grille de Brice Allenbrand image Mots croises - Grille de Brice Allenbrand image Mots croises - Grille de Brice Allenbrand image Mots croises - Grille de Brice Allenbrand


* Figure 1 : 10-By-10 word square published in 1977 in the book "Jeux de lettres, jeux d'esprit" by Michel Laclos [GRA, Ars-magna].
  REMEURTRIE : du verbe remeurtrir
  ETABLERENT : du verbe établer (mettre à l'étable)
  MATOU VESTE : phrase : "matou vesté", le second mot signifiant habillé ou investi en vieux français, ou ennivré en dialecte génevois. Exemple de phrase plausible dans un contexte de littérature médiévale : "Voyez ce fier matou vesté de son pelage noble, qui marche avec l'allure digne d'un seigneur".
  EBOULASSES : du verbe ébouler
  ULULASSENT : du verbe ululer
  REVASSANTE : de l'adjectif rêvassant
  TRESSAUTER : du verbe tressauter
  RESSENTIRA : du verbe ressentir
  INTENTERAI : du verbe intenter
  ETESTERAIS : du verbe étester (forme ancienne du verbe étêter)

* Figure 2 : 10-By-10 word square created in 2025 by Régis Petit.
This square uses five tautonymous words (each composed of two identical parts) repeated twice.
  OBAMA OBAMA :
         1. phrase : slogan "Obama ! Obama !" souvent scandé par les partisans lors d'événements en lien avec Barack Obama
         2. phrase : titre "Obama Obama" d'un livre néerlandais de Tom-Jan Meeus publié en 2009
         3. phrase : titre "Obama Obama" d'une chanson du groupe Millennium en 2008
         4. phrase : titre "Obama Obama" d'une chanson de Banjo Beats en 2020
         5. phrase : seconde partie du titre de la chanson "Felicidad America (Obama - Obama)" du groupe Boney M., selon deux versions 2009 (anglais et spanglish) adaptées de la version originale 1980 "Felicidad America (Margherita)"
  BISON BISON : phrase : nom scientifique du bison d'Amérique
  ASSIS-ASSIS : nom : terme médical du domaine de l'aide à la mobilité réduite, désignant le transfert sécurisé d'une personne d'un support assis à un autre support assis (comme d'un fauteuil à un lit en position assise), sans passer par la station debout
  MOITE-MOITE : nom : expression familière signifiant moitié-moitié
  ANSER ANSER : phrase : nom scientifique de l'oie cendrée

* Figure 3 : 10-By-10 word square created in 2025 by Régis Petit.
This square uses five tautonymous words repeated twice.
  PANGA-PANGA : nom : bois dur d'Afrique
  ARIUS ARIUS : phrase : nom scientifique du mâchoiron fouet, espèce de poisson-chat
  NIAIS ! NIAIS ! ou NIAIS, NIAIS : phrase : répétition apparaissant dans de nombreux textes dramatiques et pièces de foire. Par exemple : "O niais ! niais ! niais !" dans la pièce Othello de Shakespeare (acte V, scène II), traduite par François-Victor Hugo en 1868.
  GUILIGUILI : nom : terme familier désignant l'action de chatouiller
  ASSIS-ASSIS : nom : terme médical du domaine de l'aide à la mobilité réduite, désignant le transfert sécurisé d'une personne d'un support assis à un autre support assis (comme d'un fauteuil à un lit en position assise), sans passer par la station debout.

* Figure 4 : 9-By-9 word square published in 1975 in "Pratique des Mots Croisés" by Roger La Ferté and Jacques Capelovici (Que sais-je ? n 1624) [CRU].
  TRAMERIEZ : du verbe tramer
  REDEPENDE : du verbe redépendre
  ADONISTES : botanistes spécialistes des plantes cultivées ou exotiques, dans le contexte de la botanique horticole ancienne
  MENASSENT : du verbe mener
  EPISTANTE :
         1. Adjectif verbal féminin pouvant signifier broyante (mais non officiel en français) et formé sur le verbe épister signifiant broyer ou piler (terme de pharmacie) ;
         2. Participe présent (et adjectif verbal) du verbe portugais epistar signifiant broyer ou piler (terme de pharmacie) ;
         3. Nom du tableau "Epistante, 2019" peint par Simone Pelligrini, artiste dont l'atelier est à Bologne en Italie.
  RESSAUTER : du verbe ressauter
  INTENTERA : du verbe intenter
  EDENTERAI : du verbe édenter
  ZESTERAIS : du verbe zester

* Figure 5 : 9-By-9 word square published in 1977 in the book of Guy Brouty "Les Mots Croisés, toute une histoire" (Hachette) [CRU]. See [CHA].
  BRASSAMES : du verbe brasser
  REMEUVENT : du verbe remouvoir
  AMARRANTE :
         1. Erreur d'orthographe courante pour le nom amarante, plante relative au genre botanique Amaranthus. Cette faute se trouve souvent dans les articles culinaires.
         2. Adjectif verbal féminin pouvant signifier captivante, attachante ou qui amarre (mais non officiel en français) et formé sur le verbe amarrer ;
         3. Personnage "Amarrante" de la série d'albums pour enfants "Les Florafées" créée par H.F. Diané ;
         4. Deux villas de vacances "Borgo Amarrante" et "Molino di Amarrante" situées à Montaione en Toscane (Italie) ;
         5. Participe présent du vieux verbe italien amarrare signifiant amarrer.
  SERPENTER : du verbe serpenter
  SUREXCITA : du verbe surexciter
  AVANCERAS : du verbe avancer
  MENTIRONS : du verbe mentir
  ENTETANTE : de l'adjectif entêtant
  STERASSES : du verbe stérer

*** Figure 6 : 9-By-9 word square produced in 2007 by Christophe Lecoutre and Sébastien Tabary [LGD, Les Carrés symétriques-4].
  SACCAGENT : du verbe saccager
  AEROLOGIE : du nom aérologie
  CRAINDRAS : du verbe craindre
  COITERAIT : du verbe coïter
  ALNELOISE : de l'adjectif alnélois (relatif aux habitants de la commune d'Auneau en Eure-et-Loir)
  GODRONNER : du verbe godronner (border de godrons)
  EGRAINERA : du verbe égrainer
  NIAISERAI : du verbe niaiser
  TESTERAIS : du verbe tester

*** Figure 7 : 9-By-9 word square produced in 1996 by Laurent Bartholdi [WIK, Carré magique][WIK, Mots croisés] and communicated by Patrick Jenty [LGD, Symmetrical Squares-4].
  PACTISENT : du verbe pactiser
  ACHEMINER : du verbe acheminer
  CHARMERAI : du verbe charmer
  TERRIGENE : de l'adjectif terrigène (qui provient de l'érosion des terres)
  IMMINENTS : de l'adjectif imminent
  SIEGERAIT : du verbe siéger
  ENRENASSE : du verbe enrêner (mettre les rênes)
  NEANTISER : du verbe néantiser
  TRIESTERS : composés organiques possédant trois fois la fonction ester

*** Figure 8 : 9-By-9 word square produced in 1996 by Laurent Bartholdi [WIK, Carré magique][WIK, Mots croisés] and communicated by Patrick Jenty [LGD, Symmetrical Squares-4].
  PRECAIRES : de l'adjectif précaire
  REDONNENT : du verbe redonner
  EDENTASSE : du verbe édenter
  CONCILIER : du verbe concilier
  ANTISIGMA : lettre en forme de sigma renversé
  INALIENES : de l'adjectif inaliéné
  RESIGNONS : du verbe résigner
  ENSEMENCE : du verbe ensemencer
  STERASSES : du verbe stérer

*** Figures 9, 10 and 11 : 6 9-By-9 word squares (with alternatives) produced in 2007 by Brice Allenbrand [LGD, Les Carrés symétriques-4][ALL].
  Grille CABOSSERA
  Grille CASEMATER : Trois variantes sont possibles en remplaçant Z par E, R ou S dans RESSASSEZ
  Grille CRAMPERAS

*** Figures 12 then 13 to 24 : 43 9-By-9 word squares (with alternatives) produced in 2008 by Brice Allenbrand [LGD, Les Carrés symétriques-3][LGD, Les Carrés symétriques-2][LGD, Les Carrés symétriques-1].
  Grille ACCAPARER : Trois variantes sont possibles en remplaçant le R final par E, S ou Z dans RESSASSER
  Grille ARECACEES
  Grille ARRIVERAS
  Grille CHAMBRIER
  Grille CHASSABLE
  Grille CLASSABLE
  Grille CRAVACHEE
  Grille CRETACEES
  Grille EMECHASSE : Cinq variantes sont possibles en remplaçant le premier T par C dans ENTARTANT, et/ou U par D ou T dans ATTENUONS
  Grille EPERVIERE : Cinq variantes sont possibles en remplaçant C par T dans ENCARTONS, ou (C par S dans ENCARTONS, et premier N par S dans PUNEENNES), ou N par I dans ESSARTONS (en ligne horizontale et/ou verticale)
  Grille RAFRECHIS : Deux variantes sont possibles en remplaçant le deuxième T par R ou S dans INTERDITE
  Grille REGLABLES
  Grille RELACHERA : Quinze variantes sont possibles en remplaçant L par M dans RELACHERA (en ligne horizontale et/ou verticale), et/ou troisième S par I dans ASSONASSE (en ligne horizontale et/ou verticale)


B1.3.2. English crossword puzzles :


Word squares (1 12-By-12, 3 11-By-11 and 164 10-By-10 word squares, partial display) :

picture Crossword puzzle - Jeff Grant picture Crossword puzzle - Jeff Grant picture Crossword puzzle - Rex Gooch picture Crossword puzzle - Rex Gooch
picture Crossword puzzle - Matevz Kovacic picture Crossword puzzle - Jeff Grant picture Crossword puzzle - Jeff Grant picture Crossword puzzle - Ted Clarke
picture Crossword puzzle - Martin Laeuter picture Crossword puzzle - Dmitri Borgmannpicture Crossword puzzle - Rex Gooch picture Crossword puzzle - Rex Gooch
picture Crossword puzzle - Rex Gooch picture Crossword puzzle - Rex Gooch picture Crossword puzzle - Rex Gooch picture Crossword puzzle - Rex Gooch image Mots croises - Grille de G.H. Ropes


* Figure 1 : 12-By-12 word square produced in 2009 by Jeff Grant.
This square uses six tautonymous words repeated twice [GRA, Some of my favorite squares].
  ENDING-ENDING : noun : the conclusion of the last part of a movie, play, book, etc.
  NGONGO-NGONGO : proper noun :
         1. Locality, Bengo Province, Angola, 8 1'S, 14 32'E
         2. Stream, Sangha region, Congo, 1 33'N, 15 41'E
  DOOGOO-DOOGOO : noun : variant of dugu-dugu, the sex act, or to have sex, in modern Jamaican English slang.
  INGENS INGENS : phrase : Megascops ingens ingens, subspecies of South American Rufescent Screech-Owl.
  NGONGENGONGE : noun : clipped person in New Zealand Maori.
  GOOSEY-GOOSEY : noun : variant of goosey, a foolish person, a simpleton, for example in the well-known English nursery rhyme "Goosey-Goosey Gander".

* Figure 2 : 11-By-11 word square produced in 1987 by Jeff Grant [GRA, Quasi eleven-squares].
This square includes proper.
  CENTIGRADES : noun : thermometers using the centigrade scale.
  EX-ORGUE RIMU : phrase : a nonce-term describing rimu wood formerly used in an orgue. 'Orgue' is defined as 'any of a number of long, thick timbers, pointed and shod with iron, formerly suspended over, or in the vaulted passage behind, a gateway, to be let down in case of attack; also, these pieces collectively'.
  NOMINATIVES : noun : words in the nominative case, in grammar.
  TRITICALITY : noun : triteness.
  IGNICOLISTS : noun : worshippers of fire.
  GUACONISING : noun : variant form of 'guaconizing', treating with guano.
  RETALIATORY : adj. : tending to, involving, or of the nature of, retaliation.
  ARI LISTENER : phrase : a listening person from the small community of Ari, Indiana. For example, a conversation between a resident of Ari, and one from Fort Wayne (12 miles away) could involve a Fort Wayne speaker and an 'Ari listener'.
  DIVISIONIST : noun : an advocate of the painting method known as divisionism.
  EMETT 'N RESCH : phrase : Emett and Resch are both surnames Iisted in the 1983 Melbourne, Australia, telephone directory. The form 'n is shown in Webster's Third Edition as a shortening of 'and'.
  SUSY'S GYRTHS : phrase : a nonce-term describing the refuges of someone named Susy, back in olden times. 'Susy' is shown in What to Narne the Baby, by Evelyn Wells, as a diminutive of 'Susan'. 'Gyrth' is an obsolete form of 'grith', a refuge or sanctuary.

* Figure 3 : 11-By-11 word square produced in 2004 by Rex Gooch [GOO, The eleven-square - Take one].
This square includes foreign terms and double names associated with American first and last names.
  AABD ES SALAM : proper noun : Aabd es Salam, Syria, 36 45'N, 40 17'E
  AARON CORONA : proper noun : Aaron Corona is the U.S. Marine Corps Lance Cpl., a protective security detail team member with 3rd Battalion, 7th Marine Regiment.
  BRENDAN RUDD : proper noun : Brendan Rudd lives in Star, Idaho.
  DON FERREIRA : proper noun : Don Ferreira lives in Brentwood, California, or in Klamath Falls, Oregon.
  ENDEUTESSEN : conjugated verb : from Catalan verb endeutar-se (third person plural of the imperfect subjunctive) meaning to get into debt.
  SCARTAITELE : conjugated verb : from Romanian verb a scartai (second person singular of the imperfect indicative) meaning to creak.
  SONREIREMOS : conjugated verb : from Spanish verb sonreir (first person plural of the futur indicative) meaning to smile.
  ARRESTEREND : conjugated verb : from Deutsch verb arresteren (present participle) meaning to arrest.
  LOUISE MEADE : proper noun : Louise Meade lives in Lebanon, Indiana, or in Xichita, Kansas.
  ANDRE LONDON : proper noun : Andre London lives in Douglasville, Georgia.
  MADANE'S DENS : phrase : Madane's dens is a manufactured phrase. Madane is a locality in Oio region, Guinea-Bissau, 12 11'N, 15 19'W

* Figure 4 : 11-By-11 word square produced in 2005 by Rex Gooch [GOO, The eleven-square - Take two][GRA, Some of my favorite squares].
This square includes foreign terms and double names associated with first and last names.
  MORRIS MOSES : proper noun : Sir Morris Moses (1762-1830), later called Captain Ximenes. An alternative squares uses Norris-Moses, surname of American representational artist Dorothy NORRIS-MOSES [GRA, Some of my favorite squares].
  ORIENTIRANI : verbal adj. : oriented in Slovenian.
  RIMISURANTI : conjugated verb : from Italian verb rimisurare (present participle) meaning to remeasure.
  REID PAINTER : proper noun : Reid Painter, a pupil recorded on the 5th grade Elementary "A/B" Honor Rolls for October 2003 and January 2004 in North Chatham School, Chatham County, North Carolina.
  INSPIRADORS : noun : inspirators in Catalan.
  STUART MASON : proper noun : Dr Stuart Mason, English endocrinologist (1919-2003). A second alternative squares uses Stuart Mahon (a redident of Dublin, Ireland) and Santo Helier (a Spanish version of the name of the 6th century ascetic hermit (St. Heller), and also the capital of Jersey in the Channel Islands, which is named after him) [GRA, Some of my favorite squares].
  MIRIAM GRECO : proper noun : Miriam Greco and her husband David sold a property at 343 Barclay St, Burlington County, Philadelphia, around January 2004.
  ORANDARILOR : noun : from Romanian noun orandar (genitive or dative plural form) meaning someone who owns an inn.
  SANTOS ELLER : double proper noun : a Brazilian double surname. A Brazilian website devoted to the genealogy of the Eller family records "Maria dos SANTOS ELLER (born 3 June 1932)".
  ENTEROCOELE : noun : the body cavity formed from an outpocketing of the archenteron (a primitive digestive cavity), especially typical of echinoderms and chordates.
  SIERSNORREN : proper noun : a contrived Dutch meaning something like ostentatiously-decorated moustaches, formed by combinig sier (decorative or ornamental) with snorren (moustaches).

*** Figure 5 : 10-By-10 word square produced in 2023 by Matevz Kovacic, Sloveny [KOV][CAM].
All ten words are unique common nouns.
  SCAPHARCAE : adj. : specific epithet of bacterium name Ornithinibacillus scapharcae
  CERRATEANA : adj. : specific epithet of plant name Pitcairnia cerreteana
  ARGOLETIER : noon : a light mouted soldier ; a mounted bowman
  PROCOLICIN : noon : a propeptide form of colicin
  HALOBORATE : noon : a type of inorganic compound
  ATELOMERES : adj. : specific epithet of moth name Ectropis atelomeres
  RETIREMENT : noon : withdrawal from one's position or occupation or form active working live
  CAICARENSE : adj. : specific epithet of plant name Machaerium caicarense
  ANEITENSIS : adj. : specific epithet of tree fern name Alsophila aneitensis
  EARNESTEST : adj. : superlative form of earnest

* Figure 6 : 10-By-10 word square produced in 2006 by Jeff Grant [GRA, FISCALISED ten-square revisited][GRA, The best ten-squares].
  FISCALISED : verbal adj. : variant of fiscalized
  IMPOLARITY : noun : absence of polarity
  SPALACINES : noun : blind mole-rats of the subfamily Spalacinae
  COLDNOSERS : noun : slang for hunting dogs that follow cold trails
  ALAN BROWNE : proper noun : an American bank consultant (1908-88), in Who's Who in America, 45th Ed., 1988-89.
  LA CORALINA : proper noun : locality located in the town of Candelaria, Artemisa province, Western Cuba, 22 45'N, 82 57'W
  IRISOLONES : noun : colourless estrogenic compounds derived from certain irises
  SINEWINESS : noun : state or quality of being sinewy ; firm strength
  ETERNNESSE : noun : variant of eternness, eternity
  DYSSEASSES : noun : 16th century forms of the noun diseases

* Figure 7 : 10-By-10 word square produced in 1995 by Jeff Grant [GRA, A spooner-assisted ten-square].
  VASSALISED : verbal adj. : subdued, subjugated
  ANTELARITY : noun : a blend of antelation (preference, precedence) and priority attributed to the Reverend William Spooner when mixing up the words of 17th-century Spanish scholar James Mabber : "Alleging the antelarity of time, and priotion of his debt".
  STYRACINES : noun : white crystalline substances obtained from storax and balsam of Peru
  SERENADERS : noun : people who serenade, entertain with music
  ALAN BROWNE : proper noun : an American bank consultant (1908-88), in Who's Who in America, 45th Ed., 1988-89.
  LA CAROLINA : proper noun : town located in the Jaén province, Spain, 38 16'N, 3 37'W
  IRIDOLINES : noun : oily liquid compounds derived from coal-tar
  SINEWINESS : noun : state or quality of being sinewy ; firm strength
  ETERNNESS : noun : variant of eternness, eternity
  DYSSEASSES : noun : 16th century forms of the noun diseases

* Figure 8 : 10-By-10 word square produced in 1998 by Ted Clarke [CLA, A new Wordsworth word square][LAN].
  DISCUSSING : verbal noun : talking
  INCANTATOR : noun : one who uses incantation
  SCARLATINA : noun : scarlet fever
  CARNITINES : noun : enzymes that transport activated long-chain fatty acids across the mitochondrial membrane
  UNLIKENESS : adj. : of little ressemblance
  STATE'S WREN : phrase : little bird on flag of some US states (especially South Carolina)
  SATIN WEAVE : phrase : silk-like cloth.
  ITINERATES : conjugated verb : wanders aimlessly
  NONES EVENT : phrase : plausible festival of the ancient Romans
  GRASS NESTS : phrase : nests made by weaver birds for example

* Figure 9 : 10-By-10 word square produced in 2008 by Martin Laeuter [cf email of September 8, 2024 from Jean-Charles Meyrignac to Régis Petit].
  MADHAB PASA : proper noun : Madhab Pasa, village, babuganj upazila region, Bangladesh, 22 46'N, 90 17'E
  ARAEDAESIL : proper noun : Araedaesil, town, Chungcheongnam-do region, South Korea, 36 49'N, 126 58'E
  DAURAN NALA : proper noun : Dauran Nala, intermittent stream, Balochistan, Pakistan, 30 20'N, 67 23'E
  HERVIDEROS : proper noun : Los Hervideros, tourist site, Lanzarote island, Canary Islands, Spain, 28 57'N, 13 50'O
  ADAILE-KOMA : proper noun : Adaïlé-Koma, mountain, Djibouti, 11 29'N, 42 33'E
  BAND-E SIRAK : proper noun : Band-e Sirak, mountain, Wilayat-e Ghor Province, Afghanistan, 33 27'N, 65 7'E. An alternative square uses Band-e Zirak
  PENE-KIKILI : proper noun : Pene-Kikili, town, Maniema Province, Congo-Kinshasa, 4 36'S, 26 20'E
  ASARO RIVER : proper noun : Asaro River, river, Eastern Highlands Province, Papua New Guinea, 6 22'S, 145 12'E
  SILOMALELA : proper noun : Silomalela, village, Nias island, North Sumatra Province, Indonesia, 1 6'N, 97 39'E
  AL'ASAKIRAH : proper noun :
         1. Al'Asakirah, village, Dhamar Governorate, Yemen, 14 33'N, 44 40'E
         2. Al'Asakirah, village, Dhi Qar region, Irak, 31 0'N, 46 21'E
         3. Al'Asakirah, village, Bani Suwayf region, Egypt, 28 55'N, 30 53'E

* Figure 10 : 10-By-10 word square produced in 1973 by Dmitri Borgmann.
This square uses five tautonymous words repeated twice [BOR, A new 100-letter word square][GRA, Ars-magna].
  RABBI, RABBI : phrase : included in the verse "And greetings in the markets, and to be called of men, Rabbi, Rabbi" in "Gospel According to Saint Matthew", Chapter 23, Verse 7 (cf "The New Testament and the Book of Psalms", King James Version, published by the American Bible Society (New York, 1972)).
  A SAIL ! A SAIL ! : phrase : included in the poetic quotation "I bit my arm, I sucked the blood, And cried, A sail ! a sail !" of Taylor Coleridge in "The Rime of the Ancient Mariner", Part III, Stanza 4 (cf "Familiar Quotations" by John Bartlett, 14th Edition, Revised and Enlarged, published by Little, Brown and Company (Boston and Toronto, 1968)).
  BASSA-BASSA : noun : general confusion, noise, and, in some cases, exchange of blows (cf "Notes for a Glossary of Words and Phrases of Barbadian Dialect" by Frank A. Collymore, published by Advocate Company (Bridgetown, Barbados, 1970)).
  BISON BISON : phrase : Bison bison, scientific (genus + species) name for the bison, a hoofed animal of western North America (cf "The American Heritage Dictionary of the English Language" edited by William Morris, published jointly by American Heritage Publishing Company, Inc., and Houghton Mifflin Company (Boston, New York, Atlanta, Geneva, Illionis, Dallas, Palo Alto, California, 1971)).
  ILANG-ILANG : noun : variant spelling of ylang-ylang, a tree native to the Phillippines, Java and India (cf "The World Book Dictionary" edited by Clarerce L. Barnhart, a Thorndike-Barnhart Dictonary published exclusively for Field Enterprises Educational Corporation (Chicago, London, Rome, Stockholm, Sydney, Toronto, 1968)).

* Figure 11 : 10-By-10 word square produced in 2002 by Rex Gooch [GOO, An A to Z of ten-squares][GOO, My first ten-square].
  ABAPTISTUM : noun : abaptiston (cone-shaped trephine)
  BAHRAMTAPA : proper noun : in Azerbaijan, 39 44'N, 47 57'E
  AHLERBRUCH : proper noun : in Germany, 52 12'N, 8 29'E
  PREPARATOR : noun : a person who prepares
  TARADANOVA : proper noun : in Russia, 54 45'N, 86 41'E. An alternative square uses Tarakanova, 55 21'N, 38 57'E, also in Russia.
  IMBRANGLES : conjugated verb : old form of embrangles
  STRANGFORD : proper noun : Strangford :
         1. Village, Herefordshire, England, 51 57'N, 2 37'W
         2. Farmstead, New Zealand, 43 16'S, 172 06'E
  TAUTOLOGIA : noun : Late Latin (or Greek), whence tautology
  UPCOVERING : verbal noun : old form of up covering
  MAHRAS DAGI : proper noun : Mahras Dagi in Turkey, 36 43'N, 33 17'E

* Figure 12 : 10-By-10 word square produced in 2003 by Rex Gooch [GOO, Ten-squares with place names].
  BACKSBACKA : proper noun : Backsbacka, Finland, 63 27'N, 23 07'E
  ANHUMINAS : proper noun : Ribeirao Anhuminhas, Brazil, 22 53'S, 50 50'W
  CHAHARGAL'A : proper noun : Chahargal'a-i-Wazirabad, Afghanistan, 34 33'N, 69 09'E
  KUH-E SHAHIN : proper noun : Kuh-e Shahin, Iran, 35 24'N, 46 32'E
  SMASVALENE : proper noun : Smasvalene, Norway, 60 58'N, 4 38'E
  BI'R HASANAH : proper noun : Bi'r Hasanah, Finland, 30 27'N, 33 46'E
  ANGALACANE : proper noun : Angalacane, Mozambique, 22 28'S, 31 31'E
  CHAH-E NASIR : proper noun : Chah-e Nasir, Iran, 27 43'N, 58 01'E
  KALINANINA : proper noun : Kalinanina, Zambia, 14 23'S, 24 44'E
  ASANE HERAD : proper noun : Asane Herad, Norway, 60 28'N, 5 25'E

* Figure 13 : 10-By-10 word square produced in 2003 by Rex Gooch [GOO, Ten-squares with place names].
  BAGANBATAK : proper noun : Baganbatak, Columbia, 3 12'N, 99 40'E
  'ARAB AR RAML : proper noun : 'Arab ar Raml, Egypt, 30 31'N, 31 12'E
  GARANYEMBE : proper noun : Garanyembe, Zambia, 14 25'S, 26 56'E
  ABAG KANALI : proper noun : Abag Kanali, Azerbaijan, 39 11'N,48 36'E
  NANKUNSHAN : proper noun : Nankunshan, China, 23 38'N, 113 53'E. An alternative square uses Nankan Shan, Taiwan, 25 04'N, 121 18'E
  BRYANT BANK : proper noun : Bryant Bank, an undersea feature, 28 01'N, 92 28'W
  ARENSBURGA : proper noun : Arensburga, Estonia, 58 14'N, 22 30'E
  TAMA HARBOR : proper noun : Tama Harbor, Japan, 34 28'N, 133 56'E
  AMBLANGODA : proper noun : Amblangoda, Sri Lanka, 7 00'N, 81 11'E
  KLEIN-KARAS : proper noun : Klein-Karas, Namibia, railroad siding, 27 34'S, 18 06'E

* Figure 14 : 10-By-10 word square produced in 2002 by Rex Gooch [GRA, The best ten-squares][GOO, Some superior ten-squares][CAM].
  DESCENDANT : noun : one descended from an ancestor ; issue, offspring
  ECHENEIDAE : noun : the remora family of fishes
  SHORTCOATS : noun : people wearing short coats
  CERBERULUS : adj. : specific epithet of ant name Camponotus cerberulus
  ENTEROMERE : noun : any segment of the embryonic alimentary tract
  NECROLATER : noun : someone who worships the dead or dead bodies
  DIOUMABANA : proper noun : a populated place in eastern Guinea, West Africa, 11 16'N, 9 08'W
  ADALETABAT : proper noun : a populated place in the Mus province, eastern Turkey, 38 58'N, 42 42'W
  NATURE-NAME : noun : a toponym (place name) embodying an allusion to a natural occurrence or geographical feature
  TESSERATED : verbal adj. : rare variant of tessellated, composed of small blocks of variously coloured material arranged to form a pattern

* Figure 15 : 10-By-10 word square produced in 2002 by Rex Gooch [GOO, Some superior ten-squares].
  DESSEMBLED : verbal adj. : come from the old French verb dissembler meaning to dissemble
  EL-TAMARANI : proper noun : Wadi el-Tamarani, Egypt, 29 52'N, 34 32'E
  STITCHINGS : verbal noun : activities of sewing individual threads in something
  SATIRETTES : noun : small satires
  EMCRISTENE : noun : old form of fellow Christian. An alternative square uses emcrystene
  MAHESWARDI : proper noun : Nagar Maheswardi, Bangladesh, 24 04'N, 90 42'E,
  BRITTAINES : noun : old form of Britons
  LANTERNARO : noun : lantern maker or seller (of Italian origin)
  ENGENDERER : noun : producer, causer or bringer
  DISSEISORS : noun : persons who wrongfully dispossess

* Figure 16 : 10-By-10 word square produced in 2002 by Rex Gooch [GOO, Some superior ten-squares].
The ten words are all without separators (space, period, hyphen or apostrophe).
  DISSAVAGED : verbal adj. : civilized
  IKHATARENE : proper noun : Ikhatarene, Morocco, 33 17'N, 4 44'W
  SHORTLINGS : noun : short or small persons
  SARARESTII : proper noun : Sararestii, Romania, 44 56'N, 24 52'E
  ATTRISTING : verbal noun : saddening
  VALESTOLEN : proper noun : Valestolen, Norway, 60 49'N, 5 32'E
  ARISTOTILL : proper noun : medieval form of the proper noun Aristotle
  GENTILITEE : noun : medieval form of the noun gentility
  ENGINELESS : adj. : without an engine
  DESIGNLESS : adj. : being without a design

* Figure 17 : 10-By-10 word square produced in 1990 by G.H. Ropes [ROP, Further struggles with a ten-square].
  JAS J. ASCHER : proper noun : name of James J. Ascher found in a Kansas City telephone directory
  AQUAMARINE : noun : transparent blue-green gemstone
  SUFFISANTS : noun : citation-word plural for the obsolete adjective suffisant meaning sufficient
  JAFFA'S FORT : phrase : old military structure located in Jaffa, Palestine
  AMIATA TIER : phrase : Amiata is a mountain in the Apennine range in central Italy, part of a long chain which could plausibly be named the Amiata Tier
  SASSANIDAE : proper noun : members of the native dynasty that built and ruled an empire in Persia from 224 to 636
  CRAFTINESS : noun : cunning
  HINOIDEOUS : adj. : with veins proceeding from the midrib parallel and unbranched (venation of the leaves)
  ENTREASURE : verb : to lay up in or as in a treasury
  RESTRESSED : adj. : stressed again

* 5 other 10-By-10 word squares produced in 1990 and 2002 by Jeff Grant.
These squares include foreign terms and double names associated with American first and last names. See [GRA, A modified ten-square][GRA, In search of the ten-square].
  1 ASTRALISED square
  1 DISTALISED square
  1 DORAASCHER square
  1 INCAPABLER square
  1 MISSATICAL square

* 35 other 10-By-10 word squares (with alternatives) produced in 2003 by Rex Gooch.
These squares begin with each letter of the alphabet including separators (space, period, hyphen or apostrophe). See [GOO, An A to Z of ten-squares].
  1 BANPAKKHEN square
  1 CILASTATIN square
  2 EPICOPARI squares
  1 FABODTRASK square
  1 GATSCHAPAR square
  2 HARADSMALA squares
  1 IMPRESSUS square
  1 JASTREBACA square
  1 KACHIKAMAR square
  1 LATCHESNES square
  1 MACABABALO square
  1 MAIDENPAPS square
  1 MALENESSES square
  1 NISISASPRO square
  1 OCHIRIKROM square
  1 OMIMICREEK square
  1 PARADISIAL square
  2 PASSAGE-BED squares
  1 QALA'-I-NAMAK square
  1 RESISTLESS square
  2 SPASMODISM squares
  1 TANAMALALA square
  1 UNTUNNELED square
  1 VALEAHOGEA square
  1 WADIEL'EISH square
  1 WADIGHABAT square
  1 WALSHOUTEM square
  1 XOMBANTANG square
  2 YATTAWATTE squares
  1 ZUSAMMFALL square

* 108 other 10-By-10 word squares (with alternatives) produced in 2003 by Rex Gooch.
These squares use five tautonymous or quasi-tautonymous words, repeated twice. See [GOO, Quarter ten-squares].
  10 ABANGABANG squares
  12 ALANGALANG squares
  18 ANTINANTIN squares
  5 CLANGCLANG squares
  1 HANGIHANGI square
  1 ILANGILANG square
  27 INGITINGIT squares
  1 MANGIMANGI square
  2 ORANGOTANG squares
  1 ORANGUTANG square
  1 RENGARENGA square
  1 SANGASANGA square
  1 SANGISANGI square
  1 TANGITANGI square
  21 UNGASUNGAS squares
  1 URANGUTANG square
  1 WALLAWALLA square
  1 WANGIWANGI square
  1 WHANGWHANG square
  1 YLANGYLANG square

* 3 other 10-By-10 word squares (with alternatives) produced in 2004 by Rex Gooch.
These squares include separators (space, period, hyphen or apostrophe). See [GOO, Hunting the ten-square].
  2 NOSTOCACEA square
  1 UORESPECHE square


B1.3.3. Italien crossword puzzles :


Word squares (1 8-By-8 word square) :

picture Crossword puzzle - Italian


*** 1 8-By-8 square published in 1965 by Dmitri Borgmann [BOR, Language on Vacation, p.198].
  STACCATA : verbal adj. : detached
  TOREADOR : noun : bullfighter ; the more usual Italian word, however, is "toreadore".
  ARISTONE : noun : kind of hand organ
  CESSERAN : conjugated verb : poetic form of cesseranno meaning (they will) cease, which can be found in opera librettos
  CATENATA : verbal adj. : chained
  ADORATOR : noun : adorer
  TONATORI : noun : thunderers
  ARENARIO : adj. : sandy


B1.3.4. Spanish crossword puzzles :


Word squares (1 8-By-8 word square) :

picture Crossword puzzle - Spanish


*** 1 8-By-8 square published in 1965 by Dmitri Borgmann [BOR, Language on Vacation, p.198].
  PASAJERA : noun : female traveler
  ABATANAR : from the verb abatanar (infinitive form) meaning full cloth
  SATIRAZA : noun : fat, witty woman
  ATINARON : from the verb atinar (third person plural simple past form) meaning hit the mark : (they) hit the mark
  JARAMENA : feminine adj. : related to Jarama River in Spain. Example of use : "La ganaderia jarameña de toros"
  ENARENAR : from the verb enarenar (infinitive form) meaning cover with sand
  RAZONABA : from the verb razonar (third person singular imperfect form) meaning reason : (he) was reasoning
  ARANARAS : from the verb arañar (second person singular imperfect subjunctive form) meaning scratch : (that you) would scratch, or (if you) scratched, or (if you) were to scratch


B1.3.5. Latin crossword puzzles :


Word squares (two 11-By-11 word squares) :

picture Crossword puzzle - Eric Tentarelli picture Crossword puzzle - Eric Tentarelli


*** Figure 1 : 11-By-11 word square published in 2020 by Eric Tentarelli [TEN].
Warning: this square contains a typo in the display : the second R of the horizontal word STERILITARI must be changed to T [RPR].
  RESCISSEMUR : from the verb rescisso (first person plural future passive form) meaning discover (something unexpected)
  EXTENTERARE : from the verb extentero (infinitive form) meaning disembowel
  STENDERESIS : from the verb stendo (second person singular imperfect passive subjunctive form) defined as an apheretic form of extendo, a versatile verb whose primary meaning is extend or stretch out.
  CENSEREMINI : from the noun censeo (second person plural imperfect passive subjunctive form) meaning value, esteem
  INDEFINITAM : from the adjective indefinitus (feminine accusative singular form) meaning indefinite
  STERILITATI : from the noun sterilitas (dative singular form) meaning sterility
  SERENITATIS : from the noun serenitas (genitive singular form) meaning serenity. This particular inflected form may be familiar because Mare Serenitatis is one of the most visible features on the Moon.
  EREMITARIOS : from the adjective eremitarius (masculine accusative plural form) meaning living a hermit's life
  MARITATIONI : from the noun maritatio (dative singular form) meaning wedding or marriage
  URINATIONEM : from the noun urinatio (accusative singular form) meaning urination
  RESIMISSIMI : from the adjective resimus (masculine genitive singular of the superlative form) meaning turned up or bent back, which typically describes noses.
An alternative square is to change EXTENTERARE to EXTENTERATE (second person plural present imperative form of the same verb) and URINATIONEM to UTINATIONEM (accusative singular form of the noun utinatio meaning wish or expression of a wish).

*** Figure 2 : 11-By-11 word square published in 2020 by Eric Tentarelli [TEN].
  SCISSURAMUR : from the verb scissuro (first person plural present passive form) meaning cut (cloth, as to make garments)
  CONTENERARE : from the verb contenero (infinitive form) meaning make tender
  INFAMATORIS : from the noun infamator (genitive singular form) meaning slanderer
  STAMINAMINI : from the verb stamino (second person plural present passive form) meaning spin (thread) or support (a vine) with stakes
  SEMILIMATAM : from the adjective semilimatus (feminine accusative singular form) meaning half-polished
  UNANIMITATI : from the noun unanimitas (dative singular form) meaning unanimity
  RETAMINATIS : from the verb retamino (second person plural present form) meaning befoul, particularly with excrement
  AROMATARIOS : from the noun aromatarius (accusative plural form) meaning dealer in spices or apothecary
  MARITATIONI : from the noun maritatio (dative singular form) meaning wedding or marriage
  URINATIONEM : from the noun urinatio (accusative singular form) meaning urination
  RESIMISSIMI : from the adjective resimus (masculine genitive singular of the superlative form) meaning turned up or bent back, which typically describes noses.


B1.3.6. Serbian crossword puzzles :


Word squares (2 10-By-10 word squares) :

picture Crossword puzzle - Serbian1 picture Crossword puzzle - Serbian2


These squares, together with the Croatian squares of Anton Ferderber and Boris Babic, were published in 1999 by Miroslav Lazarevic [NAZ][ECK, The polyglot ten-square].

* 1 10-By-10 word square published in 1987 by Miroslav Lazarevni [NAZ][ECK, The polyglot ten-square][TWO]. Translation by [PER].
  SAMONAMENA : noun :
         1. sole purpose
         2. unique destination
         3. exclusive intent
  ANIMALIZAM : noun : animalism
  MILADINOVO : proper noun :
         1. Miladinovo Brdo, hill, 44 04'N, 21 28'E, located near the village of Balajnac, Despotovac Municipality, Pomoravlje district, Serbia.
         2. Miladinovo, village, Kardzhali Municipality, Kardzhali Province, Bulgaria, 41 42'N, 25 36'E
  OMANJI SITAR : phrase : little sitar
  NADIZATELJI : noun : those who surprise from above ?
  ALISA MARICH : proper noun : Serbian chess player and Minister of Youth and Sports in the Serbia Government in 2012
  MINI TALJIVA : phrase : miniature dissolving object ?
  EZOTERICHAN : adj. : esoteric
  NAVALJIVATI : verb : to push, to insist
  AMORICHANIN : noun : devotee of Cupid ?

* 1 10-By-10 word square published in 1996 by Zivota Stankovic [NAZ][ECK, The polyglot ten-square][TWO]. Translation by [PER].
  KAMATARINA : adj. : usurer's
  ABUSALATIN : noun : another name for the plant Ricinus communis. This term comes from the Arabic "habb" (grains) and "sultan" (sultan) which refers to the "grains of the sultans" (see https://jezikoslovac.com/ ).
  MUNARANINI : noun : little minaret ?
  ASALAMINIJ : phrase : and the salamis for me ?
  TARASIJEVA : adj. : Tarasije's (Tarasije = Serbian form of the Greek first name Tarasios of Constantinople)
  ALAMINARIN : adj. : without laminarin (laminarin = polysaccharide of brown algae)
  RANI JANJANI : phrase :
         1. ancient Janjani (Janjani = locality, Srebrenik Municipality, Republika Srpska, Bosnia and Herzegovina, 42 13'N, 17 28'E)
         2. early Janja inhabitants (Janja = locality, Bijeljina Municipality, Republika Srpska, Bosnia and Herzegovina, 44 40'N, 19 15'E)
         3. early Janja supporters (Janja = Janja Bec Neumann, Serbian sociologist and genocide researcher, Nobel Peace Prize winner in 2005)
  ITINERARIJ : noun : itinerary
  NINIVINICA : phrase : not even a small wine ?
  ANIJANIJAC : noun : little spell ? (anijanij = a spell in Marshall islands language)


B1.3.7. Croatian crossword puzzles :


Word squares (2 11-By-11 and 6 10-By-10 word squares, partial display) :

picture Crossword puzzle - Croatian6
picture Crossword puzzle - Croatian1 picture Crossword puzzle - Croatian2 picture Crossword puzzle - Croatian3 picture Crossword puzzle - Croatian4 picture Crossword puzzle - Croatian5


* 1 11-By-11 word square produced in 2015 by Milutin Tepsic [SRP]. Translation conforms to the definitions of this square [SRP].
  KAPETANIJAC : noun : the man who lives in the captaincy
  ANATOMIKOVI : noun : those who belong to an academician (= anatomist's group ?)
  PAZI NA SHANAC : phrase : the soldier, a guard in the trench (ditch) (= watch the trench ?)
  ETIKETARINA : noun : the fee that is paid for affixing labels
  TONEVERIZAM : noun : Verism heavy as thunder
  AMATERIJALI : adj. : immaterials
  NISHARINARAC : noun : the toll collector of the Nichava bridge
  IKARIJASHITI : verb : to fly too close to the sun
  JONIZARIZAM : noun : doctrine advocating widespread ionization
  AVANALATARI : noun : mortar tool manufacturers
  CICA MICI MISH : phrase : the modern form of the saying "Render unto Cesar what is Cesar's, to God what is God's - literally, "to the cat what it likes most to hunt" (= to the kitty its mouse ?)

* 1 11-By-11 word square produced in 2015 by Zarka Dokica [CVE]. Translation conforms to the definitions of this square [CVE].
  ARI PALEVSKI : proper noun : collaborator on the film "Virginity" (2014) directed by Saeed Khoze.
  ROSANA GITAN : proper noun : compound female name, the namesake of the Swedish actresses Munter and Goding.
  ISPREBASATI : verb : to break out
  PARAMOLORAC : noun : resident of Paramo Lora region, Cantabria Province, Spain.
  ANEMARI KIRI : proper noun : Austrian humanitarian and author of the book "My Unusual Journeys - Steps of Hope" about her experiences in the 1991-1995 war.
  LABORATORIJ : noun : laboratory
  EGALITIRANA : verbal adj. : equalized
  VISOKORODAC : noun : vegetable plants with tall trees or stems, for example corn.
  STARI RADARI: phrase : obsolete radio-locators
  KATARINA ROJ : proper noun : a young member of the women's hockey club "Boston Samrocks"
  INICIJACIJA : noun : customs and rites (almost among all primitive peoples) by which a boy is declared a boy, and a girl a girl.

* 1 10-By-10 NASTRANOST word square produced in 1941 by Anton Ferderber [DNE][NAZ].
* 1 10-By-10 NADPRILIKA word square produced in 1984 by Boris Babic [BLO][NAZ].
* 1 10-By-10 PERIPATUSI word square produced in 1987 by Boris Babic [ENI][NAZ].
* 1 10-By-10 TIPSKAZENA word square produced in 2010 by Antun Cvitkovic [DNE][DNE2][NAZ].
* 1 10-By-10 OSTANIDOMA word square produced in 2020 by Boris Babic, Resad Besnicanin, Zarko Dokic, Antun Juric, Nedjeljko Nedic, Ilija Ozdanovac and Georgi Zeravica [DOM].
* Other 10x10 word squares including that of Zarka Dokica [CVE].


B1.3.8. Hungarian crossword puzzles :


Classic crossword puzzles (1 9-By-9 crossword puzzle) :

picture Crossword puzzle - Hungarian


* 1 9-By-9 crossword puzzle published by CPT [CPT]. Translation by [PER].
Horizontally :
  KI SZELNEK : phrase : "who are cutting ?"
  RAZAROEBA : ?
  IZEGOKNEK : adj. : to those who fidget
  SAROSIIDE : adj. : Saros's (Saros = former department of Hungary, 49 00'N, 21 14'E)
  ZSEREITEK : adj. : Zs re's (Zs re = another name for Zirany, Nitra region, Slovakia, 48 23'N, 18 10'E)
  TINIITEKE : phrase : to your teenagers
  ABANDOKEN : ?
  BANKEKERA : phrase : towards the bank group ?
  ANKETENEK : phrase : for his/her survey
Vertically :
  KRISZTABA : phrase : into Kriszta (Kriszta = diminutive of Krisztina)
  IAZASIBAN : phrase : in the Iaz region
  SZERENANK : ?
  ZAGORINKE : proper noun : Zagorin's ?
  EROSEIDET : phrase : your strong ones ?
  LOKI I TOKE : phrase ? : the Loki bow and its arrow rest ?
  NENITEKEN : phrase : on your aunt
  EBEDEKERE : phrase : towards your lunches ?
  KAKEKENAK : ?


B1.3.9. Hebrew crossword puzzles :


Classic crossword puzzles (1 10-By-10 crossword puzzle) :

picture Crossword puzzle - Hebrew


* 1 10-By-10 crossword puzzle published by CPT [CPT]. Partial list of words translated by [PER] :
Horizontally :
  1- she shoshbinotayikh : phrase : "who are her bridesmaids ?"
  12- keshelkhem yirkhtu : phrase : when it belongs to you, they buy it
  19- ve se ototeihem : phrase : and that theirs signs
Vertically :
  1- shel keshe shukhlelu : phrase : of when they were perfected
  10- ha havayati'im : phrase : the experiential aspects


B1.3.10. German crossword puzzles :


Word squares (17 8-By-8 and 4 7-By-7 word squares) :

picture Crossword puzzle - German
picture Crossword puzzle 1 - German picture Crossword puzzle 2 - German picture Crossword puzzle 3 - German


*** 2 8-By-8 crossword puzzles (with alternative) created by Claude in 2026 [CLAU].
  BLANKSTE : declined adj. : shiniest, barest
  LINEATUR : noun : ruling (a pattern of lines)
  ANRUDERN : verb : to approach by rowing
  NEUWERTE : noun : replacement values
  KADENZEN : noun : cadences
  STERZELN : verb : to raise the abdomen (of bees)
  TURTELTE : conjugated verb : billed and cooed (figuratively, flirted)
  ERNENNEN : verb : to appoint or name. An alternative square uses ERNENNET meaning : (that) you appoint or name.

*** 8 8-By-8 crossword puzzles (with alternatives) created by Claude in 2026 [CLAU].
  FLUGWEGE : noun : flight paths
  LINEARER : declined adj. : linear
  UNDANKES : declined noun : of ingratitude
  GEANKERT : conjugated verb : anchored. An alternative square uses GEACKERT meaning : worked hard, slogged.
  WANKENDE : conjugated verb : wavering, tottering
  ERKENNER : agent noun : one who perceives, understands
  GEERDETE : declined adj. : grounded, earthed
  ERSTERER : declined adj. : the former. Three alternative squares use ERSTEREM, ERSTEREN, ERSTERES in other declined versions.

*** 2 8-By-8 crossword puzzles (with alternatives) created by Claude in 2026 [CLAU].
  ATEMWEGE : noun : airways, respiratory tract
  TARIEREN : verb : to tare (balance a scale)
  ERHELLST : conjugated verb : (you) illuminate, clarify
  MIETKAUF : noun : rent-to-own (purchase)
  WELKENDE : declinated adj. : wilting
  ERLANGET : conjugated verb : (that) you attain, obtain
  GESUDELT : conjugated verb : scribbled, smeared messily. An alternative square uses GESUDERT (regional, rare) meaning : worked hard, slogged.
  ENTFETTE : conjugated verb : degreases

*** 2 8-By-8 crossword puzzles (with alternatives) created by Claude in 2026 [CLAU].
  HERZASSE : noun : ace of hearts
  EREILTER : declined adj. : overtaken, caught up with (by fate)
  RENNBAHN : noun : racetrack
  ZINNERNE : declined adj. : made of tin, pewter
  ALBERTEN : conjugated verb : (they/we) fooled around
  STARTERN : declined noun : to the starters
  SEHNERVS : declined noun : of the optic nerve. An alternative square uses SEHNERVE in other declined version.
  ERNENNST : conjugated verb : (you) appoint, name. The same alternative square uses ERNENNET meaning : (that) you appoint or name.

*** 1 8-By-8 crossword puzzle created by Claude in 2026 [CLAU].
  LEIHAMTS : declined noun : of the pawnshop, loan office
  ERNEUERE : conjugated verb : (I) renew
  INZESTEN : declined noun : to incest cases
  HEERBANN : historical noun : feudal call to arms
  AUSBILDE : conjugated verb : (I) train
  METALLER : noun (colloquial) : metalworker
  TRENDELE : conjugated verb (regional) : (I) dawdle
  SENNEREI : noun : Alpine dairy farm

*** 2 8-By-8 crossword puzzles (with alternative) created by Claude in 2026 [CLAU].
  WEGWARFT : conjugated verb : (you) threw away
  EGRENIER : conjugated verb : gin (cotton) ! (separate fibers from seeds)
  GRÖLENDE : declined adj. : bawling, singing loudly
  WELLIGEN : declined adj. : wavy
  ANEIFERN : regional verb : to spur on, encourage
  RINGELTE : conjugated verb : curled, colled
  FEDERTEN : conjugated verb : (they) were springy, bounced
  TRENNEND : conjugated verb : separating. An alternative square uses TRENNENS meaning : of separating (declined noun).

*** 1 7-By-7 crossword puzzle published in 2022 by the magazine Süddeutsche Zeitung [SUD].
  SAMSARA : noun : samsara
  ANAEROB : adj. : anaerobic
  MAPPEUR : noun : mapper
  SEPTOLE : noun : septuplet (musical technical term)
  AEROPAG : noun : Areopagus (supreme court in ancient Athens)
  ROULADE : noun : roulade
  ABREGEN : verb : to cool down

*** 2 7-By-7 crossword puzzles (with alternative) created by Tim in 2022 [GIB].
  FIEBERT : conjugated verb : (he) has a fever. An alternative square uses SIEBERT meaning (regional technical term) : (he) filters.
  INNERER : declined adj. : inner
  ENDLOSE : declined adj. : endless
  BELEBEN : verb : to revive
  EROBERN : verb : to conquer
  RESERVE : noun : reserve
  TRENNEN : verb : to separate

* 1 7-By-7 crossword puzzle created by Tim in 2022 [GIB].
  BEATLES : proper noun : Beatles
  EINHEIT : noun : unit
  ANREISE : noun : journey
  THEATER : noun : theater
  LEITERN : noun : ladders
  EISERNE : adj. : iron
  STERNEN : declined noun : stars



Sources relating to crossword puzzles :


B1.4. Mnemonics

picture Mnemomicspicture Mnemomics2

  1. Introduction
  2. Recall table of figures from 0 to 9
  3. Recall table of numbers from 00 to 99
  4. Sources


B1.4.1. Introduction :

Mnemonics encompasses all the techniques designed to facilitate the memorization and recall of information through mental associations.
Among these methods, the number articulation method [WIK] stands out for its effectiveness in remembering numbers. This system is based on a fixed correspondence between the numbers 0 to 9 and consonant sounds. For example, 3 corresponds to the sound "m". By freely adding vowels, sequences of numbers are transformed into concrete words that are easier to memorize. For example, the number 42 can become the word mouton (m = 3, t = 1).
The recall table of figures (from 0 to 9) was developed in the 19th century by Aimé Paris [PAR, p.28] and then adopted identically by Abbé François-Napoléon-Marie Moigno [WIK]. A different, simpler version was later proposed by Joe Bertin [BER] in 2028, and adopted almost identically by Régis Petit in 2025.
The recall table of numbers from 00 to 99 assigns a specific word to each of these numbers.

The steps of the number articulation method are as follows :
1. Associate each number from 0 to 9 with a consonant sound, according to a code to be memorized (see Recall table of figures).
2. Convert the sequence of numbers to be memorized into a sequence of sounds, according to this code.
3. Form a sequence of words from these sounds by adding vowels, so as to phonetically create a sentence, or mentally create a vivid and memorable story.
4. To reproduce the numbers, proceed in reverse : story, words, sounds, numbers.

Example of a story in French that you can create yourself to remember the first decimals of the number Pi = 3, 14 15 92 65 35 89 79 32 38... :
- According to the recall table of figures by Aimé Paris : "assis par TeRre sur une modeste ToiLe, je suis en PaNne et GèLe. Au loin, près d'une MeuLe de foin, se trouve une VamP portant une CaPe de MoiNe et des MouFles."
- According to the recall table of figures by Régis Petit : "sur mon TanK, à côté d'une TaSse, d'une PoiRe et d'une GouSse d'ail, j'écoute la MeSse, quand surgit un BiP sonore. J'éclaire avec ma LamPe et vois une MaRe avec un MeuBle en plein milieu."

Applications :
Among the applications where the number articulation method provides real benefits, we can cite :
- Telephone numbers encoded into 5 concrete words of two digits each (example : 06 12 34 56 78)
- Anniversary dates encoded into 4 concrete words (example : 24 02 1958)
- Access codes (PIN code, building door code, safe code, alarm code, etc.) encoded into 2 or 3 concrete words depending on their length
- Social security numbers encoded into an initial digit (gender : 1 male, 2 female) followed by 7 concrete words (example : 1 58 02 XX XX XX XX XX)


B1.4.2. Recall tables of figures from 0 to 9 :

The recall table of figures from 0 to 9 is not unique and depends on its author :
- Aimé Paris's table has the merit of codifying all common consonant sounds. The association between figure and sound(s) must be memorized.
- Joe Bertin's table associates a consonant letter with each figure, which provides a visual aid that greatly facilitates sound memorization.
- Régis Petit's table reproduces Joe Bertin's table, modifying the letters associated with the figures 2 and 4, which improves the visual aid (see Figure above).
The different tables are as follows :
Table legend : (*) according to the orthographic writing of the phonemes.

FigureSong (*) and image according to Aimé Paris [PAR, p.28][WIK][APP]Other image according to Régis PetitSong (*) and image according to Joe Bertin [BER]Song (*) and image according to Régis Petit
0"s" or "z", one of the loops of the letter sSanS aide"d", letter D"d", letter D
1"t" or "d", single leg of the letter tTenDu ou Tout Droit"t", letter T"t", letter T
2"n" ou "gn", double leg of the letter nNa ! (attitude enfantine de provocation)"n", letter N sideways"r", letter R without a vertical bar
3"m", triple leg of the letter nMaman"m", letter M sideways"m", letter M sideways
4"r", upside-down or mirrored letter rtrois Ratures faites avec Rage"r", letter R mirrored"k", letter K (with a block of three strokes)
5"l", similar to the letter L in French cursive round writing [LIV1][LIV2]Ligne verticale ratatinée"s", letter S"s", letter S
6"ch" or "j", similar to the letter j in French cursive round writing [LIV1][LIV2]Chat qui Jaillit"g" ou "j", letter G"g" ou "j", letter G
7"k" or "g", gallows shape similar to the letter q or gCoups Guerriers (indiqués par deux Coupures)"l", letter L upside-down"l", letter L upside-down
8"f" or "v", similar to the letter F in French cursive round writing [LIV1][LIV2]FèVe (sous forme de petit enFant)"b", letter B"b", letter B
9"p" or "b", mirrored letter p or upside-down letter bPetit Bébé (en position foetale avec sa grosse tête)"p", letter P mirrored"p", letter P mirrored


B1.4.3. Recall tables of numbers from 00 to 99 :

Anyone can freely construct their own recall table of numbers from 00 to 99, based on a given recall table of figures.
The recall tables of numbers from 00 to 99 proposed below were created by Régis Petit. The first is based on Aimé Paris's coding of figures, the second on Régis Petit's coding of figures.
These two tables are designed according to the following rules for easy memorization of concrete words :
    Concrete word = common or proper noun, with a single syllable of the CVC or CSVC type, such as :
    C = consonant associated with the figure in the recall table of figures.
    V = vowel that can be (*) : "é" "è" "eu" "in" "a" "an" "ou" "o" "on" "i" "u"
    S = semi-consonant at the onset of a V vowel, which can be (*) : "w" "y" "u+"
    The V or SV nucleus of the syllable is chosen primarily from the sounds (*) : "é" "è", "eu", "in"; "a", "an" ; "ou", "w" V ; "o", "on" ; "i", "y" V ; "u", "u+" V
(*) according to the orthographic writing of the phonemes.
Exceptions to these rules are in italics in these tables.

NumberConcrete word conforming to Aimé Paris's coding of figuresConcrete word conforming to Régis Petit's coding of figures
00SasDinde
01SouteDatte
02ScèneDard ou Dur
03SommeDame
04Serre ou SoeurDock ou Duc
05SelleDanse
06SoucheDanger ou Dingue
07SacDalle
08SoifDab ou Daube
09SepDieppe ou Dupe
10TasseTiède
11Tête ou TenteTête ou Tente
12TonneTerre
13TomeTome
14TerreTank
15ToileTasse
16TacheTige ou Tag
17TankToile
18TouffeTombe
19TaupeTaupe
20NasseRade
21NatteRate
22NonneRire
23NemRame
24NerfRack
25NulRace
26NicheRage ou Reg
27NuqueRâle
28NefRab ou Robot
29NappeRampe ou Repas
30MesseMode
31Meute ou MotteMeute ou Motte
32MoineMer ou Mare
33MômeMôme
34Mer ou MareMec
35Meule ou MalleMesse
36MècheMage ou Mangue
37MecMeule ou Malle
38MoufleMeuble
39MyopeMyope
40RaceCoude
41RateQuinte ou Côte
42ReineCoeur
43RameCame
44RireCake
45RâleCaisse
46RocheCage
47RackCale
48Rouf ou RêveCube
49RâpeCoupe ou Cape
50LaisseSoude
51LatteSoute
52LaineSerre ou Soeur
53LameSomme
54LardSac
55LilleSas
56LoucheSinge ou Sangle
57LacSel
58LympheSabre
59LoupeSoupe
60ChasseJade ou Guide
61Jante ou ChatteJatte ou Goutte
62Jeune ou ChaîneJour ou Gare
63Gym ou ChaumeGym ou Gamme
64Jour ou ChairJonque
65Gel ou ChâleGousse
66JugeJuge ou Gong
67Jonque ou ChèqueGel ou Gueule
68ChefJambe
69Jupe ou ChappeJupe ou Guêpe
70CaisseLad ou Lande
71Quinte ou CôteLatte
72CanneLard
73CameLame
74CoeurLac
75CaleLaisse
76CoucheLinge ou Langue
77CakeLille
78CoiffeLobe
79Coupe ou CapeLampe
80FesseBande
81FêteBête
82FouineBeurre
83FemmeBoum
84FerBanque
85Foule ou FilBosse
86Fiche ou VacheBouge ou Bague
87FacBalle
88FiefBob
89VampBip
90PincePanda ou Poudre
91PattePatte
92PannePoire
93PommePomme
94PèrePack ou Pique
95PellePanse
96PêchePage
97Pack ou PiquePelle
98PoufPub ou Poubelle
99Pape ou PoubellePape


B1.4.4. Sources relating to Mnemonics :

[APP] Apprendre5minutes, Comment mémoriser facilement les chiffres ou les nombres
[BER] Joe Bertin, Astuce de mémorisation : la table de rappel
[LIV1] French Handwriting Schoolbook, écriture ronde française
[LIV2] pilllpat (agence eureka), album Alphabete
[PAR] Aimé Paris, Exposition et pratique des procédés mnémotechniques à l'usage des personnes qui veulent étudier la mnémotechnie en général comme un moyen d'abréger l'étude de toutes les connaissances humaines, Paris, 1825
[WIK] Wikipedia, Code chiffres-sons



B1.5. Palindromes

picture Palindromes

  1. Introduction
  2. Attributed palindromic sentences
  3. Anonymous palindromic sentences
  4. Palindrome cities
  5. palindrome first names
  6. Word palindromes
  7. Numeric palindromes
  8. Rotational palindromes
  9. Mirror palindromes
  10. Musical palindromes
  11. Sources


B1.5.1. Introduction :

A palindrome is a form of linguistic symmetry where a sentence (which can be as short as a single word) reads or sounds the same in both directions. See Attributed palindromic sentences, Anonymous palindromic sentences, Palindrome cities and Palindrome first names.
Orthographic palindromes are based on the order of letters in writing, as in "C'est sec".
The same applies to word palindromes that are based on the order of words in writing, as in "Un pour tous, tous pour un" or in "La juste est juste là" (for a non-strict palindrome).
The same applies to syllabic palindromes at the syllable pronunciation level, as in "Laconique Nicolas", corresponding to the syllabic sequence "la" "ko" "ni" "ke" "ni" "ko" "la".
The same applies to phonetic palindromes at the phoneme pronunciation level, as in "Il aima Amélie", corresponding to the phonetic sequence "i" "l" "é" "m" "a" "a" "m" "é" "l" "i".
The same applies to numeric palindromes at the writing level, as in the date "02/02/2020".
The same applies to Rotational palindromes at the writing level, as the word "inoui".
The same applies to mirror palindromes which read identically after reflection in a mirror.
The same applies to musical palindromes at the level of the notes of the musical phrase.

The palindromes listed below are exclusively orthographic palindromes in the French language, where case (upper/lower case), diacritical marks (accent, diaeresis, cedilla, tilde, etc.), spaces and punctuation marks (period, comma, dash, parentheses, etc.) are not taken into account.


B1.5.2. Attributed palindromic sentences :

The most beautiful palindromic sentences in the French language, attributed to an author, are the following :

A Cuba, Anna a bu ça (Gérard Durand).
A Laval, elle l'avala (Michel Laclos).
A l'étape, épate-la ! (Louise de Vilmorin).
A révéler mon nom, mon nom relèvera (Edmond Rostand, dans Cyrano de Bergerac).
Ce satrape repart à sec (Pierre Bailly).
C'est sec (Roger Cornaille).
Eh ! ça va la vache ? (Louise de Vilmorin).
Elisa, là, à l'asile (Lennig Gullon).
Elu par cette crapule (Charles Cros).
Emile-Eric, notre valet, alla te laver ton ciré élimé (Georges Perec).
Engage le jeu que je le gagne (Alain Damasio).
En nos repères, n'insère personne (Dominic Bergeron).
En route je tourne (Roger Cornaille).
Eric, notre valet, alla te laver ton ciré (Jacques Capelovici).
Esope reste ici et se repose (Jacques Capelovici).
Etel, un port trop nu, l'été (Claude Gaignière).
Et la Marine va venir à Malte (attribué à Victor Hugo).
Et Luc colporte trop l'occulte (Michel Laclos).
Karine égarée rage en Irak (Gérard Durand).
Karine libre à Erbil en Irak (Christophe L.)
La Marine en ira mal (attribué à Victor Hugo).
La mariée ira mal (Louise de Vilmorin).
L'âme des uns n'use de mal (Etienne Pasquier).
L'amer vin enivre mal (Jean T.).
La mère Gide digère mal (Louis Scutenaire).
L'âme sûre ruse mal (Louise de Vilmorin).
L'ami naturel ? Le rut animal ! (Louise de Vilmorin).
Lune de ma dame d'été, été de ma dame de nul (Louise de Vilmorin).
Nier est effet serein (Stéphane Susana).
Noël a trop par rapport à Léon (Sylvain Viart).
Oh ! cet écho (André Tomkins).
Par-delà le drap (Patrick Hospital).
Rions noir (Jacques Bens).
Rue Verlaine gela le génial rêveur (Jacques Perry-Salkow).
Ta bête te bat (Louise de Vilmorin).
Un art luxueux ultra nu ! (Matthieu Godbout).
Un émir fada, venu du Nevada, frime nu (Gérard Durand).


B1.5.3. Anonymous palindromic sentences :

The most beautiful palindromic sentences in the French language, without a known author, are the following :

A l'autel elle alla, elle le tua là.
Bon sport, trop snob.
Car, tel Ali, il a le trac.
Ce mec.
essayasse.
Etna : lave dévalante.
Etre là, alerte.
Et se resservir, ivresse reste.
Et Tesio, né borné et naïf, emporte une vedette devenue trop méfiante en robe noisette (Francis Pacherie).
Ici.
Il a pâli.
Il a sali.
Karine alla en Irak.
L'âge légal.
La malade pédala mal.
L'âme d'Eve rêve de mal.
La mère puce récupère mal.
L'âne vénal.
malayalam (langue parlée en Inde).
mon nom.
Nie, reste net, serein.
Ni lac, ni patelin, ni le tapin câlin.
Oh ! Cela te perd, répéta l'écho.
ressasser.
Réussir à Paris : suer.
rotavator.
S'engager à revers : rêver à regagnes !
Sexe vêtu, tu te vexes ?
Ta belle porte s'use trop, elle bat.
Trace là mon nom à l'écart.
Un drôle de lord nu.
Un ému a son os au menu.
Un enfer bref. Né nu.
Un été nu.
Un rêve de ver nu.
Un roc lamina l'animal cornu.
Un roc si biscornu.
Zeus a été à Suez.


B1.5.4. Palindrome cities :

The main palindrome cities of the world are the following :

Allemagne : Burggrub (Bavière), Hammah (Basse-Saxe), Mussum (Rhénanie-du-Nord-Westphalie), Woddow (Brandenburg), Zeez (Mecklenburg-Vorpommern)
Angola : Seles (Cuanza Sul)
Arabie Séoudite : Al'Ula (Madinah)
Argentine : Neuquén (Patagonie)
Australie : Aramara (Queensland), Arrawarra (Nouvelle-Galles-du-Sud), Civic (Territoire de la Capitale Australienne), Glenelg (Adélaïde, Australie-Méridionale), Hattah (Victoria), Lal Lal (Victoria), Parap (Territoire du Nord), Paraparap (Victoria), Tumut (Nouvelle-Galles-du-Sud)
Belgique : Eke, Ellemelle (Province de Liège), Ere
Brésil : Aba (Bahia), Acaiaca (Minas Gerais), Aia (Ceara), Mutum (Minas Gerais)
Burkina Faso : Bob (Région du Centre-Ouest)
Canada : Elôle (Québec), Kinikinik (Alberta), Laval (Québec), Navan (Ontario), Salas (Nouvelle-Ecosse), Wakaw (Saskatchewan)
Chili : Lolol (O'Higgins)
Chine : Nan'an (Fujian)
Danemark : Dragsgard, Vellev
Egypte : Aga (gouvernement de Daqahliyya)
Espagne : Aba (Pays basque), Aja, Aya, Oco, Ollo (Navarre), Oro, Oso (Catalogne), Salas (Asturie), Saras, Senés (Andalousie), Sotos
Etats-Unis : Ada (Oklahoma, Oho, Minnesota), Ala (Alabama), Anna (Ohio, Texas, Illinois), Ava (Missouri, Illinois, New York), Capac (Michigan), Civic (Canberra), Eleele (Hawaï), Hannah (Michigan, Dakota du Sud, Caroline du Nord), Harrak (Oklahoma, Washington), Ixixi (Alaska), Kanakanak (Alaska), Kinikinik (Colorado), Level (Ohio, Maryland), Noxon (Montana), Otto (plusieurs Etats), Oto (Iowa), Remer (Minnesota), Renner (Texas), Wassamassaw (nom d'une région de Caroline du Sud)
Ethiopie : Asasa, Asosa
Finlande : Asa (Laponie), Esse, Ii (Ostrobotnie), Orö
France : Afa, Callac, Esse, Eve, Eze, Laval, Noron, Noyon, Oô, Sajas, Sanas, Saras, Savas, Sées, Selles, Senones, Serres, Sos, Sus
Grèce : Sedes, Serres
Groenland : Qaanaaq (Région Qaasuitsup)
Hongrie : Tat, Tét, Pap, Ziliz
Inde : Ara (Bihar), Aramara, Atta (Uttar Pradesh), Aya (Maharashtra), Gadag (Karnataka), Idappadi (Tamil Nadu), Itamati (Odisha), Rapar (Gujarat), Nawagawan
Iran : Barab, Basab, Kahak, Karak, Kuruk, Naran, Qoroq, Sarras, Selles, Sis, Sus, Tabbat
Irlande : Navan (Comté de Meath)
Israël : Akka, Na'an
Italie : Ala (Trentin-Haut-Adige), Ateleta (Abruzzo), Erre (Podesteria, ancien nom), Onano (Latium), Onno (Lombardie), Sennes (Tyrol du Sud), Siris (Calabre)
Japon : Aka (Fukuoka), Akasaka (Tokyo, Okayama), Ama (Shimane), Awa (Tokushima), Ono (Préfecture de Hyogo)
Mali : Tamahamat, Tassassat
Maroc : Akka, Assa
Mauritanie : Tétêt (Région de l'Adrar)
Niger : Tabadabat, Tassessat
Nigeria : Aba (Etat d'Abia), Abiriba, Apapa, Elele (Rivers), Irri, Ososo, Oyo (Etat d'Oyo)
Nouvelle-Zélande : Aka Aka (Auckland)
Pays-Bas : Ede (Province de Gueldre), Ee (Province de Groningue), Epe (Province de Gueldre)
Pologne : Wolow (Basse-Silésie)
République tchèque : Vokov
Roumanie : Anina (Judet de Caras-Severin)
Royaume-Uni : Anna (Suffolk), Eve (Ecosse), Eye (Cambridgeshire, Suffolk), Glenelg (Ecosse), Notton (West Yorkshire, Angleterre)
Russie : Aga (République de Sakha) Tommot (Iakoutie), Ulu (Iakoutie), Yessey (Krasnoïarsk)
Sénégal : Matam (Région de Matam)
Suède : Abba (Province de Dalécarlie), Dörröd, Kivik, Murum
Suisse : Planalp (Obwald)
Thaïlande : Nan (Province de Nan)


B1.5.5. Palindrome first names :

The main palindrome first names are the following :
Legend : (*) indicates the most common palindrome first names in France (born in France or listed in the INSEE "First Names" database since 1900).

Female first names :
Ada (*), Adda
Aa
Anevena
Anina
Anona
Arezera
Afifa
Aviva
Aia, Aya
Arora
Atta
Ece
Elle (*)
Eve (*)
Hawah, Hawwah
Immi
Ireri
Ivi
Izzi
Layal
Lenel
Malayalam
Maram
Okko
Viv

Male first names :
Aba, Abba
Alla
Aoloa
Bob (*)
Did
Efe
Lehel
Nan
Natan (*), Nattan
Nayan
Neven
Odo
Oto, Otto (*)
Reber
Reinier
Sabas
Savas
Talat, Tanat

Unisex first names :
Aja (*)
Ama (*), Amma
Ana (*), Anna (*), Anena, Hannah (*)
Ara
Asa
Ava (*), Awa
Axa
Aza, Azza, Aziza
Civic
Ebbe
Ede
Eme, Emme (*)
Görög
Kajak, Kayak
Lil (*), Lyl
Noon
Nosson
Ono
Siris
Uru
Yay
Zaz


B1.5.6. Word palindromes :

Word palindromes are phrases that read identically from right to left and from left to right at the word level, regardless of case (upper/lower case) and punctuation marks (period, comma, dash, parentheses, etc.), as in the following examples :
Un pour tous, tous pour un
Papa aime maman, maman aime papa
Nous avions les avions, nous !
Pierre baise à Baise-Pierre

Some word palindromes, less strict, allow the omission of diacritical marks (accent, diaeresis, cedilla, tilde, etc.), as in the following examples :
La juste est juste là
La foule, foule-là !
Saint-Pierre a marié Marie à Pierre Saint


B1.5.7. Numeric palindromes :

The major numeric palindrome are the following [PAL][VIL] :

02-02-2020
21-12-2112
121 = 38 + 83 = 121
12 345 678 987 654 321 which is the square of palindromic number 111 111 111
982 623 644 294 744 275 088 611 239 676 071 787 170 676 932 116 880 572 447 492 446 326 289 which is the square of non-palindromic number 31 346 828 297 209 660 045 268 842 120 992 233 (July 5, 2024 - Patrick De Geest)
1 030 607 060 301 which is the cube of palindromic number 10 101
1 331 000 039 930 000 399 300 001 331 which is the cube of palindromic number 1 100 000 011
10 662 526 601 which is the cube of non-palindromic number 2 201


B1.5.8. Rotational palindromes :

Rotational palindromes (also called "rotational ambigrams") are words or phrases that read identically after rotating the entire set halfway.
This property applies exclusively to the following characters [AMB][DEL] :
Digits : 0, 1, 8, which remain invariant under rotation, and 6/9 which are rotation pairs of each other.
Punctuation marks : - : () [] {} which remain invariant under rotation.
Symbols : + - / x = ≠ ∞ \ ∫ ⊗ # $ % | θ ι ο χ which remain invariant under rotation.
Capital letters : H, I, N, O, S, X, Z, which remain invariant under rotation, and M/W which are rotation pairs of each other.
Lowercase letters : i, l, o, s, x, z, which remain invariant under rotation, and a/e, b/q, d/p, h/y, m/w, n/u, which are rotation pairs of each other.

The most beautiful rotational palindromes are the following :
NON
SOS
SONOS
NOW NO SWIMS ON MON (qui signifie "Maintenant plus de piscine le lundi")
NeW MaN
aie
axe
aune
yeah
apode
inoui
sales
saxes
suons
nounou
salles
saisies
saillies
elle alla
andin basnoda a une épouse qui pue (Georges Perec).

Note that some words can give rise to another word by rotating it halfway. Examples :
91 = 90 + 01 / 10 + 06 = 19
NOM/WON
NOS/SON
las/sel
epis/sida
eues/sana
iles/sali
oued/pano
sans/sues
ailes/salie
aillé/allié
esses/sassa
assassins/suissesse
le pou / nodal

Also note that some words can give rise to the same word or another word by rotating them a quarter turn. Examples :
Counterclockwise (where the capital letters C E H I M N O X Z become respectively U W I H E Z O X N) :
OHIO/OHIO
MON/ZOE
ZOE/WON
con/cou
Clockwise (where the capital letters E H I N O U W X Z become respectively M I H Z O C E X N) :
OIE/OHM
ZOE/NOM


B1.5.9. Mirror palindromes :

Mirror palindromes are words or phrases that exhibit axial symmetry, either horizontally or vertically, and read identically when viewed in a mirror held horizontally or vertically.
Horizontal symmetry reverses top and bottom, while preserving left and right and the order of the letters. BEC in a horizontal mirror remains BEC.
Vertical symmetry reverses left and right as well as the order of the letters within the word, while preserving top and bottom. TOUT in a vertical mirror becomes TUOT.
These symmetry properties applie exclusively to the following characters [AMB][DEL] :

Horizontal symmetry :
Numbers : 0, 1, 3, 8
Punctuation marks : . - : () [] {}
Symbols : + - x = > < ∑ ∞ ∫ ⊗ | € ε θ ι κ ο χ
Uppercase letters : B, C, D, E, H, I, K, O, X
Lowercase letters : c, i, k, l, o, x

Vertical symmetry :
Numbers : 0, 1, 8
Punctuation marks : . - : " '
Symboles : + - ± x = * ∏ ∞ ⊗ _ | γ θ ι ν ο π τ υ χ ψ ω
Uppercase letters : A, H, I, M, O, T, U, V, W, X, Y
Lowercase letters : i, l, m, o, u, v, w, x

Examples of mirror palindromes with horizontal symmetry :
BEC
BICHE
DIODE
EXCEDEE
kilo

Examples of mirror palindromes with vertical symmetry :
TOT
AVIVA (3ème personne du singulier du passé simple du subjonctif du verbe aviver MAOAM (marque de bonbons pâte à mâcher d'origine allemande)
MATAM (ville du Sénégal)
TAMAT (3ème personne du singulier de l'imparfait du subjonctif du verbe tamer)
TATAT (3ème personne du singulier de l'imparfait du subjonctif du verbe tâter)
TAXAT (3ème personne du singulier de l'imparfait du subjonctif du verbe taxer)
HAITI, AH !
MOT A TOM
wow (interjection d'origine anglaise exprimant la surprise ou l'émerveillement)


B1.5.10. Musical palindromes :

picture Musical palindrome


Musical palindromes are sound sequences constructed to remain identical when played in either direction, according to two possible types of symmetry :
- Retrograde (B), which consists of replaying the sequence of notes (A) in reverse order in time. Example (see Figure above) : The original sequence Do Ré Mi Fa Sol La Si La Sol Fa generates the inverse sequence Fa Sol La Si La Sol Fa Mi Ré Do.
- Inversion (C), which consists of replaying the sequence of notes by reversing the direction of the intervals between these notes around an imaginary horizontal axis. Example (see Figure above, with Do chosen as the reference point for the horizontal axis) : The sequence Do Ré Mi Fa Sol La Si La Sol Fa generates the inverse sequence Do Sib Lab Sol Fa Mib Réb Mib Fa Sol.
- The retrograde of inversion (D), which consists of combining these two processes. Example (see Figure above) : The combination of the two previous examples generates the sequence Sol Fa Mib Réb Mib Fa Sol Lab Sib Do.

Warning : Palindromic inversion (C) is different from inversion of an interval or chord in music.

Depending on the composer, pieces A, B, C and D can be mixed in sequence or superimposed. For example :
In Guillaume de Michaut ("My End Is My Beginning") : Superimpose A + B + C', where the Tenor voice is an integral part of A.
In J.S. Bach (Musical Offering, Canon Cancrizans, or Canon Per Motum Contrarium) : Superimpose A + B or sometimes superimpose A + D
In Haydn (Symphony No. 47, Minuet of the Palindrome) : Sequence A then B then C then superimpose A + D


B1.5.11. Sources relating to Palindromes :

[AMB] Wikipedia - Ambigramme
[DEL] Jean-Paul Delahaye, Ambigrammes, revue Pour la Science, N 323, Septembre 2004
[DUR] Gérard Durand, Palindromes en folie
[PAL] The Palindrome, Palindrome ?
[QUI] Quillbot, Palindromes
[RED] reddit, Quelle est la plus grande ville du monde qui porte un nom palindromique ?
[STA] StarinuX, Liste de palindromes
[VIL] Gérard Villemain, Langue - Palindromes - Villes
[VIL] Gérard Villemain, Formes- Palindromes - Introduction
[VIL] Gérard Villemain, Formes - Palindromes - Dates
[VIL] Gérard Villemain, Formes- Palindromes - Carrés
[VIL] Gérard Villemain, Formes- Palindromes - Cubes
[WIK] Wikipedia, Palindrome
[WIK] Wikipedia, Liste des palindromes en français
[WIK] Wikipedia, Palindrome (multilangues)



B1.6. Magic tricks

Here is a collection of spectacular magic tricks.

Contents :

  1. Magic tricks with ropes or rubber bands
  2. Magic tricks with playing cards
  3. Magic tricks with numbers
  4. Sources



B1.6.1. Magic tricks with ropes or rubber bands :

Here are some spectacular tricks using ropes, rubber bands or just your hands.

  1. Hands turned over
  2. Battery swap between two hands
  3. The traveling ring
  4. Bouncy rubber band between fingers
  5. Bouncy rubber band between hands
  6. Intertwined rubber bands
  7. String handcuffs puzzle
  8. Escape with bound hands


B1.6.1.1. Hands turned over :

picture Hands turned over


This trick is a popular cognitive psychology experiment.
A spectator is asked to interlace their fingers, palm to palm, in an inverted position, and then turn them over.
This slightly uncomfortable position exposes both rows of fingers to the upwards (see Figure above).
A specific finger is then pointed out without being touched, and the spectator is asked to raise it quickly and without thinking.
The spectator then frequently raises the opposite, symmetrical finger.
This error arises from a conflict between an internal representation of the fingers, disrupted by the unusual posture, and the automatic motor commands, designed for hands in a normal position. Vision could correct this, but not quickly enough when an immediate response is required.


B1.6.1.2. Battery swap between two hands :

picture Hand to Hand Switcheroo with batteries


This dexterity trick involves swapping two round AA batteries from one hand to the other without dropping them or using any special effects.
The manipulation is simple and quick, but difficult for a spectator to reproduce.
The steps are as follows (see Figure above, cf. [PRA][ASH]) :
1. Hold a round AA battery in the crook of each thumb and index finger, pinching the battery in the middle, slightly angled towards the wrist, with the bottom (negative pole) facing the palm.
2. Position your hands facing the spectator, palms hidden, in head-to-tail position, with your fingers horizontal and in a vertical plane.
3. Rotate your right hand a quarter turn counterclockwise.
4. Bring your hands together, keeping your fingers parallel, with your right thumb sliding under your left thumb.
5. Place each thumb on the bottom of each battery and loop each miidle finger over the other end of the batteries (positive pole).
6. Pinch each battery between your thumb and middle finger, then gently separate your hands.
7. Rotate both hands slightly to present the two batteries vertically to the spectator. 8. Return the batteries to their initial position (step 1) by reversing the steps.

Note : Instead of pinching the batteries between thumb and middle finger, you can also do it between thumb and index finger (as shown in the Figure above), but this finger position during the cross-locking (step 5) is more forced and less comfortable.


B1.6.1.3. The traveling ring :

picture The traveling ring


1. This spectacular trick requires a ring and a cut not-too-bright rubber band approximately 10 cm long (see Figure above, cf. [MIR]).
2. Coil the rubber band in your left hand, leaving about 1 cm of the end sticking out. Pinch the end firmly between your thumb and index finger, then pass the rubber band through the ring.
3. Grasp the rubber band between the thumb and index finger of your right hand, tender it to the maximum, and tilt it slightly upwards. The ring will naturally stop against your left hand.
4. Without moving either hand, the ring will then begin to slowly slide up the rubber band.
Solution : After stretching the rubber band, let it slide gently between the thumb and index finger of your left hand, causing the ring to slide up.


B1.6.1.4. Bouncy rubber band between fingers :

picture Bouncy rubber band between fingers


This magic trick requires a small, brightly colored rubber band.
The steps are as follows (see Figure above, cf. [CAR2]) :
1. Facing the spectator, hold the rubber band above a vertical hand.
2. Loop the rubber band around the index and middle fingers of this hand.
3. Press your fingers and thumb against the rubber band and close your fist, saying this aloud.
4. Blow on your fingers and reopen your fist. The rubber band will suddenly jump and wrap around the other two fingers.
Explanation : Just before closing your fist, grasp the rubber band between the thumb and index finger of your other hand (5a), pull it quickly down to the base of your palm (5b), close your fist (5c), and place the rubber band at the base of your four fingernails, starting with your little finger and working towards your index finger (5d). Then open your fist (5e).
Improved solution : To better conceal this secret manipulation, before closing the fist, grasp the rubber band, pull it back with your index finger while pressing your palm against your wrist, thumb and other fingers facing the spectator, close your fist, lower your arms under the table, place the rubber band on your fingers, re-press the wrist, and show the whole thing unchanged to the spectator. Then open your fist.


B1.6.1.5. Bouncy rubber band between hands :

picture Bouncy rubber band between hands


This magic trick requires two rubber bands of the same color and quite long.
The steps are as follows (see Figure above, cf. [MAGE]) :
1. Present your open palm to the spectator, with a rubber band around the top of your thumb and the base of your other four fingers.
2. Using the index finger of your other hand, gently peel the rubber band away from your palm to clearly demonstrate that it is normal.
3. Present your other hand upside down and tap your fingers together.
4. Raise your thumb. The rubber band will suddenly jump onto the four fingers of your other hand.
Solution : Prepare the rubber band as follows :
5a. Place the rubber band around your wrist, on the palm side, then in the hollow between your thumb and your index finger.
5b. Press your thumb firmly against your index finger to secure the rubber band, then turn your hand over so your palm is facing up.
5c. Pass the rubber band between the top of your thumb and index finger, maintaining pressure.
5d. Turn your hand over so your palm is facing down, then pass the loop of the rubber band around your four fingers.
5e. Turn your hand over again, palm up, with the rubber band positioned at the base of your four fingers.
5f. Pull the rubber band slightly to pass it over the top of your thumb.
5g. Place a second rubber band around your wrist to conceal the secret preparation.
The preparation is now complete, and the trick can begin in front of a spectator.


B1.6.1.6. Intertwined rubber bands :

picture Intertwined rubber bands


This magic trick requires two small, identical rubber bands of the same color.
The steps are as follows (see Figure above, cf. [JER]) :
1. Hold one rubber band vertically between the thumb and forefinger of your left hand, and another between the thumb and middle finger of your right hand, with the two rubber bands intertwined.
2. Move both hands by bringing them together and moving them apart, and also by rotating them in opposite directions, to show the spectator that the system is locked.
3. Suddenly separate your hands. Both rubber bands will be released.
Solution :
4a. As you rotate your hands, pass your right index finger, which is free, through the loop of your right thumb.
4b. Push your right index finger in and pass it behind the left rubber band.
4c. Remove your right middle finger from the right rubber band.
4d. The rubber band will automatically move over your right index finger.
4e. Immediately press the rubber band against the other one to simulate the lock.
4f. Suddenly move your hands apart.
Improved solution (cf. [PAU][VAL]) :
In step 1, hold the rubber band horizontally (and not vertically), which avoids passing behind the left rubber band in step 4b.


B1.6.1.7. String handcuffs puzzle :

picture String Handcuffs Puzzle


This spectacular trick is the following :
1. Two people are standing facing each other (see Figure above, cf. [EIT]).
Each person's wrists are connected by a rope approximately 1 meter long, forming a loose loop around each wrist and secured with a knot that is assumed to be unbreakable.
The two ropes are intertwined, thus connecting the two people.
How can they separate without cutting the rope, without untying the knots, and without the rope slipping down their hands ?
Solution :
2. Make a Bight (loop in the shape of an elongated U) with your own rope behind your partner's rope.
3. Pass the Bight through the loop around your partner's wrist, from the arm towards the fingers.
4. Pass the Bight over your partner's hand.
5. Pull on the rope : it miraculously comes undone, and the two people are then completely separated.


B1.6.1.8. Escape with bound hands :

picture Escape with bound hands


This magic trick requires only a rope approximately 70 cm long.
The steps are as follows (see Figure above, cf. [CAR1]) :
1. Place a table between you and the spectator and show a "very strong rope" stretched taut between your two hands.
2. Lay the rope on the table, parallel to the spectator.
3. Place your left hand in the middle of the rope, palm facing up.
4. Bring the right end of the rope over your left wrist, and in front of the left end.
5. Bring the left end of the rope over your right wrist, without crossing the other end.
6. Place your right hand on top of your left hand, palm facing down.
7. Ask the spectator to take the two free ends and tie them together above your hands with three tight knots.
8. Raise your arms, showing your hands tied together.
9. Lower your hands behind the table and then immediatly... raise your free right hand.
10. Lower your free hand behind the table and then immediatly... raise both hands again.
11. Repeat steps 9 to 10.
12. Lower your hands behind the table and then immediatly... raise both hands.
Explanation : Behind the table, rotate each wrist a quarter turn in the opposite direction (13a, 13b, 13C, 13d) and take the right hand out of the loop (13e). Reverse the movement to reattach both hands.

Note : a more sophisticated version of this trick exists (see [HAF]).


B1.6.2. Magic tricks with playing cards :

Here are some spectacular card tricks that can be done by children.

  1. The thieving Jacks
  2. The four Kings
  3. The four Aces
  4. The found card
  5. Magical memorization
  6. The 27-card trick
  7. The three-card monte


B1.6.2.1. The thieving Jacks :

picture The thieving Jacks


This trick requires a 32-card deck :
1. Take three Jacks from a deck of cards and leave the deck face down on the table.
2. Tell the story : "Three thieves want to break into a house...
3. The first finds a basement window and goes through the cellar (place a Jack under the deck).
4. The second climbs onto the roof and goes through the attic (place a Jack on top of the deck).
5. The third finds an open window and goes down to the ground floor (insert a Jack into the deck)."
6. Ask the spectator to "cut" the deck.
7. Announce that the three Jacks will be together and fan out the deck to verify this.
Solution : Prepare the deck by placing a Jack (the fourth) on top. The three Jacks reunited at the trick end are not the same, but this often escapes the spectator.


B1.6.2.2. The four Kings :

picture The four Kings


This trick is a variant of the "Three thieves" trick. It requires a 32-card deck :
1. Fan out the four Kings in front of the spectator.
2. Stack them on top of the remaining deck.
3. Take the four top cards one by one and insert them into the deck.
4. Ask the spectator to "cut" the deck into two approximately equal parts.
5. Announce that the four Kings will be together and fan out the deck to verify this.
Solution : Before starting the trick, discreetly add a stack of four more cards under the fan of the four Kings, well hidden by the first King (see Figure above).


B1.6.2.3. The four Aces :

picture The four Aces


This trick requires a 32-card deck :
1. Give the spectator a deck of cards to shuffle, then take the deck back, and present it vertically, facing the spectator.
2. Ask him to take one of the Aces and place it face down against his chest.
3. Pass the deck behind your back, then show it to the spectator again, asking him to replace his Ace in the deck.
4. Give the deck back to the spectator to shuffle, then take the deck back, and remove the chosen Ace.
Solution :
- Prepare the deck by setting the "point" of each Ace in the card center in the same orientation (spades, hearts, clubs), the Ace of diamonds being symmetrical (see Figure above).
- Behind your back, turn the deck of cards halfway around (top/bottom reversed).
- The chosen Ace is the Ace of diamonds if no "point" is reversed, and the Ace with a reversed "point" otherwise.
- Warning : Remove the chosen Ace from the deck, thumb pointing towards you, then present the card to the spectator, thumb pointing towards him (this reverses the card's orientation so the trick can be repeated). Then place the card back in the deck, thumb pointing towards the spectator.

Note : In terms of face cards (Jack, Queen, King, and Joker), numbered cards (from Ace to Ten), and possible indexes placed in opposite corners, standard post-19th-century French 54-card decks generally feature cards that are symmetrical by rotating them a half turn. There are 18 exceptions : the two Jokers (red and black), the four Sevens (one for each suit), and four triplets of cards (spades, hearts, clubs) corresponding to Aces, Threes, Fives, and Nines.


B1.6.2.4. The found card : :

picture The found card


This trick is a spectacular and little-known generalization of the "Four Aces" trick. It requires a 32-card deck :
1. Give the spectator a deck of cards to shuffle, then take the deck back, and present it vertically, facing the spectator.
2. Ask him to take any card and place it face down against his chest.
3. Pass the deck behind your back, then present it to the spectator again, asking him to replace his card in the deck.
4. Give the deck back to the spectator to shuffle, then take the deck back, present it fanned out, quickly scroll through the cards one by one, and remove the chosen card.
Solution :
- Not every deck of cards has perfect printing in the center of each card. The white band separating the top edge of the card from the top of its printed portion (the short side of the rectangle surrounding each face card, or the head of each number) is not identical at the top and bottom of the card. With few exceptions, each card therefore has a small band and a large band.
- Prepare the deck by setting the small band on the same side throughout. If the band is almost identical at the top and bottom of the card, discard the card from the deck.
- Behin your back, turn the deck of cards halfway around (top/bottom reversed).
- When scrolling through the cards, aim for the top band. The chosen card is the one whose band suddenly changes size (small/large) due to a stroboscopic effect.
- Warning : Remove the chosen card from the deck, thumb pointing towards you, then present the card to the spectator, thumb pointing towards him (this reverses the card's orientation so the trick can be repeated). Then place the card back in the deck, thumb pointing towards the spectator.


B1.6.2.5. Magical memorization :

picture Magical memorization


This spectacular trick requires a 32-card deck :
1. Shuffle the deck.
2. Pass the deck behind your back, move the bottom card to the top, and present the deck vertically, facing the spectator.
3. Announce the card and repeat from step 2.
4. Continue in this way with all the cards in the deck.
Solution :
- At the end of the shuffle, discreetly memorize the last card on the bottom of the deck.
- While presenting the deck to the spectator, memorize the bottom card that is facing you.


B1.6.2.6. The 27-card trick :

picture The 27-card trick


This purely mathematical trick requires a 32-card deck :
1. Make a deck of exactly 27 cards.
2. Fan out the deck to the spectator. Ask him to mentally remember a card C and then to give a number N from 1 to 27. Secretly calculate the number R = N - multiples of 9, adjusting R between 1 and 9 (examples : if N = 18, then R = 9 ; if N = 22, then R = 4).
3. Turn the deck face down and arrange the cards face up on the table in three columns of nine cards each, placing them in horizontal rows of three, from left to right and from top to bottom (see Figure above).
4. Ask the spectator to point to the column containing his card, then stack the cards, face up and column by column, picking up the designated column in the position p = R - multiples of 3, adjusting p between 1 and 3 (example: if R = 4, then p = 1). More simply, column p is immediately visible without any calculation by distributing R in a 3x3 square, in horizontal rows of 3, from left to right and from top to bottom (see Figure above).
5. Turn the deck face down again and form three columns of nine cards each again, as before, and ask for the column again. Stack the cards, face up and column by column, picking up the designated column in position q = 1 + Int[(R - 1)/3] (example : if R = 4, then q = 2). More simply, column q is immediately visible without any calculation by distributing R in a 3x3 square, in vertical columns of 3, from top to bottom and from left to right (see Figure above).
6. Turn the deck face down again and form three columns of nine cards each again, as before, and ask for the column again. Locate card C in position R of this column. Stack the cards, face up and column by column, picking up the designated column in position r = 1 + Int[(N - 1)/9] (example : if N = 22, then r = 3). More simply, column r is immediately visible without any calculation by distributing N in a 9x3 rectangle, in vertical columns of 9, from top to bottom and from left to right (see Figure above).
7. Turn the deck face down and place the cards one by one face down on the table, counting from 1. On the Nth card, announce card C and turn it face up.

Demonstration :

Let p, q and r be the order numbers (between 1 and 3) in which the designated column is picked up at each spread of the cards in three columns.
Let Np, Nq and Nr be the position in the deck (between 1 and 27) of the first card in the block containing card C, after picking up the designated column p, q or r, and reforming the deck.
At each spread, the exact position of card C in the deck is not determined, but rather the position of the first card in the block containing it. The size of this block is divided by 3 at each step.

At the first spread, the deck of 27 cards is divided into 3. After picking up column p and reforming the deck, card C is mechanically located in a continuous block of 9 cards, the position of the first card of which is :
Np = 1 + 9(p - 1), corresponding to the interval Ip = [Np, Np + 8].
Examples :
If p = 1, Ip = [1, 9].
If p = 2, Ip = [10, 18].
If p = 3, Ip = [19, 27].

At the second spread, this block of 9 cards is divided into 3. After picking up column q and reforming the deck, card C is mechanically located in a continuous block of 3 cards, the position of the first card of which is :
Nq = 9(q - 1) + 1 + (Np - 1)/3 = 1 + 9(q - 1) + 3(p - 1), corresponding to the interval Iq = [Nq, Nq + 2].
Examples :
If p = 1 and q = 1, Iq = [1, 3].
If p = 1 and q = 2, Iq = [10, 12].
If p = 2 and q = 1, Iq = [4, 6].
If p = 2 and q = 2, Iq = [13, 15]
If p = 3 and q = 1, Iq = [7, 9]

At the third spread, this block of 3 cards is divided into 3. After picking up column r and reforming the deck, card C is mechanically located in a block of only 1 card, whose position is :
Nr = 9(r - 1) + 1 + (Nq - 1)/3 = 1 + 9(r - 1) + 3(q - 1) + (p - 1), corresponding to the interval Ir = [Nr, Nr].
Examples :
If p = 1, q = 1 and r = 1, Ir = [1, 1].
If p = 1, q = 1 and r = 2, Ir = [10, 10].
If p = 1, q = 2 and r = 1, Ir = [4, 4].
If p = 1, q = 2 and r = 2, Ir = [13, 13].
If p = 2, q = 1 and r = 1, Ir = [2, 2].
If p = 2, q = 1 and r = 2, Ir = [11, 11].
If p = 2, q = 2 and r = 1, Ir = [5, 5].
If p = 2, q = 2 and r = 2, Ir = [14, 14].
If p = 3, q = 1 and r = 1, Ir = [3, 3].

Given the expression for Nr, the number N at the end of the trick satisfies the formula : N - 1 = 9(r - 1) + 3(q - 1) + (p - 1)
This trick is therefore simply a decoding of the number (N - 1) into base 3, column by column, where each column choice provides one of the three ternary digits.

Given this formula, the simplified expressions for p, q, and r are then as follows :
We set R = (N - 1) mod 9 + 1 = N - multiples of 9, adjusting R between 1 and 9
p = (N - 1) mod 3 + 1 = (R - 1) mod 3 + 1 = R - multiples of 3, adjusting p between 1 and 3 = column of the square p(R) in Figure above.
q = Ent[(N - 1)/3] mod 3 + 1 = Ent[(R - 1)/3] + 1 = column of the square q(R) in Figure above.
r = Ent[(N - 1)/9] + 1 = column of the rectangle r(N) in Figure above.



B1.6.2.7. The three-card monte :

picture The three-card monte - Initial layout and double pinch    picture The three-card monte - Standard shuffle without cheating


The Three-card monte (bonneteau) is a street card game where a player must locate the red card among three cards after a rapid shuffle.
Required equipment :
- A rigid tablet or thick cardboard serving as a table.
- Three cards : two black (for example, the King of spades and the King of clubs) and one red (the Queen of hearts).
- Cash for the player's bets.
The monte operator (bonneteur) is a professional manipulator who presents the game, shuffles the cards, and runs the play.
The player places a bet and points to the card they believe is the red.
The shills (barons) are the operator's accomplices. They pretend to play and win to build confidence, attract passersby, watch for police, and calm losers.
In France, three-card monte is illegal as it constitutes a game of chance played in public with money stakes (Article L. 324-1 of the Internal Security Code).

Game rules :
1. The operator shows the three cards face up and places the red between the two black cards. The cards are slightly folded lengthwise to make them easier to grip by the short edges when they are face down (see Figure 1 above [TUT]).
2. He turns over the cards, face down, and shuffles them quickly on the table with linear movements.
3. The operator turns over the middle card, which hasn't changed (red). He turns it over again and performs a second shuffle that appears identical to the first.
4. The player then places a bet and points to the card (left, center, right) they think is the red.
5. The operator reveals the chosen card. If it's the red, the player receives double their bet. Otherwise, the bet is lost.
In practice, the game is rigged :
1. The operator often starts with a few honest, slow rounds where the shills win easily to gain the public's confidence.
2. Once a real player participates, the operator alters his manipulations :
   - Index rotation drop : A specific two-card grip allowing independent release of the top or bottom card. This "double pinch" technique is ideal for prolonged shuffles.
   - Filage (sliding) : Discreet sliding of one card under another.
   - Quick swap : Concealed swap of two cards at the moment of placement.
   - Result : The operator always maintains control of the red' true position.

Index rotation drop technique [TUT] :
The index rotation drop technique consists of discreetly releasing the top card (black) while retaining the bottom card (red).
- Initial position : The top card (black) is held between thumb and index at the two corners. The bottom card (red) is held identically but between thumb and middle finger. Both cards share a common thumb pivot point, while a small wedge-shaped gap exists between their opposite edges (see Figure 2 above [TUT]).
- Execution : Turn the wrist to clearly show the red to the player, then reposition palm facing the table. During the linear movement above the table, the index performs a sharp but discreet rotation, releasing pressure on the top card (black). It slides passively forward, while thumb/middle finger firmly hold the bottom card (red).
- End of movement : The dropped card seems to follow the continuity of the shuffle and is always the bottom card.
- One-handed double drop [TUT, 04:20] :
   - Initial layout of the cards on the table, as seen by the player : N1 R N2 (N = black, R = red).
   - Two cards are picked up in double pinch : first N1 as top card, then R as bottom card. Turn the wrist to clearly show R to the player.
   - Perform first drop of card (N1) by placing it in the middle, then the remaining card (R) to the left, secretly transforming the layout to R N1 N2.
   - Pick up two other cards in double pinch : first R as top card, then N2 as bottom card. Turn the wrist to clearly show N2 to the player.
   - Perform second drop of card (R) by placing it to the right, then the remaining card (N2) to the left, secretly transforming the layout to N2 N1 R.
   - The player is doubly tricked, thinking R is either in the middle or to the left.

Standard shuffle technique :
The standard shuffle is performed in three rhythmic phases (see Figure 3 above and [TUT, 03:58]) :
- Phase 1 : Central drop. Place one of the two cards held in double pinch at the center using the index rotation drop technique.
- Phase 2 : Five Croiser-Ecarter sequences :
   - Croiser : Pass a card over the one immediately to its left (or right).
   - Ecarter : Move an outer card to the right (or left), creating a temporary empty space for another card.
   - The five sequences systematically alternate sides (Left/Right) per the binary pattern : Croiser L - Ecarter R | Croiser R - Ecarter L | Croiser L - Ecarter R | Croiser R - Ecarter L | Croiser L - Ecarter R
- Phase 3 : Final Croiser. Croiser once more to the Right.
When the shuffle is executed without cheating, with a drop of the bottom (red) card, the initial N1 R N2 layout remains unchanged, reinforcing the illusion of a neutral process.


B1.6.3. Magic tricks with numbers :

Here are some spectacular number-based tricks.

  1. Mind reading
  2. The age of children
  3. The Maurice Dagbert's trick


B1.6.3.1. Mind readind :


[narrated by Clément Brizzard]

This spectacular trick is a magical mind-reading experiment.
The magician asks a member of the audience to think of a whole number between 1 and 100,
then multiply it by 9,
then subtract 5,
then add the digits of the resulting number,
then repeat this last operation if the result is greater than 9,
then convert the result into a letter of the alphabet : A for 1, B for 2, C for 3, etc.,
then think (in French) of a European country beginning with that letter,
then think (in French) of a fruit beginning with the last letter of the European country.
The magician then announces that the fruit thought of is a "kiwi". If the person says this is incorrect, then the magician announces that the fruit is a "kaki".
At no point did the person speak.

Explanation :
Any integer N with n digits is of the form cn...c2c1 and can be written :
N = 10n - 1 cn + ... + 100 c3 + 10 c2 + c1 = (10n - 1 - 1) cn + ... + 99 c3 + 9 c2 + (cn + ... + c3 + c2 + c1)
Therefore, N is of the form : N = 9K + sum S of the digits of N.
If S is greater than 9, then similarly : S = 9K' + sum S' of the digits of S.
In conclusion, every number N is always the sum of a multiple of 9 and a remainder between 1 and 9 corresponding to the simple or repeated sum of the digits of the number N.
Example 1 : 8 = 9 x 0 + 8, where 8 is the digit of the number 8.
Example 2 : 34 = 9 x 3 + 7, where 7 is the sum 3 + 4 of the digits of the number 34.
Example 3 : 38 = 9 x 4 + 2, where 2 is the sum 3 + 8 = 11 of the digits of 38, and then the sum 1 + 1 of the digits of 11.
If N is already a multiple of 9 (as requested by the magician), then this remainder is necessarily 9.
Subtract 5 from this N, which is a multiple of 9, so the remainder is 4.
The only European country beginning with the letter D (corresponding to 4 in the alphabet) is "Danemark" (in French).
The only common fruits beginning with a K (corresponding to the last letter of the word "Danemark") are "kiwi" and "kaki" (in French).
Hence the magician's answer, without any mind reading.

Improved solutions :
- Offer to choose N between 1 and 10 rather than between 1 and 100.
- Multiply N by 10 and then subtract N, rather than multiplying N by 9.
- We can repeat the trick a second time, but with a different person, and with the following modification : Instead of asking for a European country, ask directly for a fruit whose name begins with the letter of the alphabet (which gives the "Datte" corresponding to the result 4 = D).
- We can repeat the trick a third time with any person, asking them to subtract 7 instead of 5. Then, instead of asking for a European country, ask directly for a fruit whose name begins with the letter of the alphabet (which gives the "Banane" corresponding to the result 2 = B).


B1.6.3.2. The age of children :

picture The age of children


A father is talking to the mail carrier : "I have three children. The product of their ages is equal to 36. The sum of their ages is equal to the number of the house across the street."
The mail carrier looks at this number and asks : "I'm missing one piece of information to solve the problem.
" The father replies : "That's right. My oldest is blond."
The mail carrier then gives the solution. How did he do it ?

Solution to this riddle :
36 can be obtained in 8 different ways :
1 x 1 x 36, which adds up to 38
1 x 3 x 12, which adds up to 16
1 x 4 x 9, which adds up to 14
1 x 6 x 6, which adds up to 13
2 x 2 x 9, which adds up to 13
2 x 3 x 6, which adds up to 11
3 x 3 x 4, which adds up to 10
Since the mail carrier couldn't determine the sum by looking at the house number, this indicates that the sum has several possibilities, not just one.
Only 13 is ambiguous, and since there's only one eldest child, the children are therefore 2, 2, and 9 years old.


B1.6.3.3. The Maurice Dagbert's trick :

picture The Maurice Dagbert s trick


[Heard on the radio in the 1980s]

A famous French calculating prodigy, Maurice Dagbert, presented this seemingly impossible problem :
"Choose an integer between 1000 and 3000 [2139 was given]. I will now calculate two lists of 17 integers each, such that :
- The sums of the numbers are equal to 2139,
- The sums of the squares of the numbers are equal,
- The sums of the cubes of the numbers are equal,
and so on up to the sixth power of the numbers.
Furthermore, all numbers will be different from each other, whether within a list or between lists."
For the number N = 2139 chosen, he then stated, after only a few minutes, the following two lists :
    First list (La) = [ 59, 63, 68, 82, 86, 100, 105, 109,    139, 143, 148, 156, 162, 173, 175, 185, 186 ]
    Second list (Lb) = [ 60, 61, 70, 79, 89, 98, 107, 108,    140, 141, 151, 153, 164, 170, 178, 183, 187 ]
A computer confirmed the calculations.

The explanation is as follows :

1. Mathematical modeling :
The problem can be written as the following system of equations S, with k = 6, n = 17, and Sum = N.
(1) System S :
    ∑iai = ∑ibi = Sum
    ∑iai2 = ∑ibi2
    ∑iai3 = ∑ibi3
    ...
    ∑iaik = ∑ibik
where :
    i = index from 1 to n
    n = size of each list
    k = power of the termes of last equation
    Sum = sum of the terms of first equation
    ai and bi = positive integers, all distinct

2. First tip :
Each list of 17 numbers is actually a concatenation of two sublists of 8 and 9 numbers each, satisfying the following subsystems S1 and S2 :
(21) Subsystem S1 = System S for k = 6, n = 8 and Sum = N1, corresponding to the following partial lists :
    L1a = [ 59, 63, 68, 82, 86, 100, 105, 109 ]
    L1b = [ 60, 61, 70, 79, 89, 98, 107, 108 ]
(22) Subsystem S2 = System S for k = 6, n = 9 and Sum = N1, corresponding to the following partial lists :
    L2a = [ 139, 143, 148, 156, 162, 173, 175, 185, 186 ]
    L2b = [ 140, 141, 151, 153, 164, 170, 178, 183, 187 ]
(23) Additional condition : N1 + N2 = N

3. Second tip :
Each of these subsystems is known in mathematics as the "PTE (or Prouhet-Tarry-Escott) Problem" [WIK1].
This problem has the remarkable property of being invariant under translation of variables [WIK1]. If we replace the variables ai and bi respectively with (a*i = α ai - β) and (b*i = α bi - β), where α and β are any two constants, then the new variables are solutions to the same problem by simply changing Sum to Sum* = (α Sum - n β).
This translation allows us to normalize the solutions, for example, by requiring that they be positive and that zero be included.

For S1, if we choose α1 = 1 and β1 = 84, we obtain the translated subsystem S1* as follows :
(31) Subsystem S1* = subsystem S1 of sum N1* = N1 - 8 β1, corresponding to the following translated lists :
    L1a* = [ -25, -21, -16, -2, 2, 16, 21, 25 ]
    L1b* = [ -24, -23, -14, -5, 5, 14, 23, 24 ]
This solution, called even-sized and symmetric [WIK1], is of the form [ -c4, -c3, -c2, -c1,    c1, c2, c3, c4 ] for the first list and [ -d4, -d3, -d2, -d1,    d1, d2, d3, d4 ] for the second.
This symmetry automatically makes equations in odd powers valid in subsystem S1*, which can be simplified to :
Subsystem S1* :
    n = 4
    ∑ici2 = ∑idi2
    ∑ici4 = ∑idi4
    ∑ici6 = ∑idi6
corresponding to the following basic lists :
    C1 = [ ci ] = [ 2, 16, 21, 25 ]
    D1 = [ di ] = [ 5, 14, 23, 24 ]

For S2, if we choose α2 = 1 and β2 = 163, we obtain the translated subsystem S2* as follows :
(32) Subsystem S2* = subsystem S2 of sum N2* = N2 - 9 β2, corresponding to the following translated lists :
    L2a* = [ -24, -20, -15, -7, -1, 10, 12, 22, 23 ]
    L2b* = [ -23, -22, -12, -10, 1, 7, 15, 20, 24 ]
This solution, called odd-sized and symmetric [WIK1], is of the form [ -c5, -c4, -c3, -c2, -c1,    d2, d3, d4, d5 ] for the first list and [ -d5, -d4, -d3, -d2,    c1, c2, c3, c4, c5 ] for the second.
This symmetry automatically makes equations in even powers valid in subsystem S2*, which can be simplified to :
Subsystem S2* :
    n = 5
    ∑ici = ∑idi
    ∑ici3 = ∑idi3
    ∑ici5 = ∑idi5
    with d1 fictitious = 0
corresponding to the following basic lists :
    C2 = [ ci ] = [ 1, 7, 15, 20, 24 ]
    D2 = [ di ] = [ 0, 10, 12, 22, 23 ]

Furthermore, the symmetry of the solutions, for each subsystem S1* and S2*, makes the sums N1* and N2* zero, which can be written :
(33) N1 = 8 β1 and N2 = 9 β2
Given relation (23), this gives the following necessary condition :
(34) N = 8 β1 + 9 β2
Note that this condition is always attainable, since 8 and 9 are coprime.

4. Choice of a solution for subsystem S1* :
Subsystem S1* (see relations (31)) is that of the PTE problem of size n = 4 and specific powers k = 2, 4, and 6.
Several solutions have been known since 1913, including the following [SHU1] :
    [ 2, 16, 21, 25 ] = [ 5, 14, 23, 24 ]
    [ 7, 24, 25, 34 ] = [ 14, 15, 31, 32 ]
    [ 7, 31, 36, 50 ] = [ 18, 20, 41, 49 ]
    [ 9, 47, 49, 67 ] = [ 23, 31, 61, 63 ]
The first solution is the smallest solution in non-negative integers for these three powers [SHU2].
It is highly probable that Maurice Dagbert knew these solutions and used the first one.

5. Choice of a solution for subsystem S2* :
The S2* subsystem (see relations (32)) corresponds to the PTE problem of size n = 5 and specific powers k = 1, 3, and 5.
While published solutions are scarce, they can be found analytically. The approach involves pairing elements from the two lists and then solving the resulting quadratic system using an appropriate method, such as that by elimination of variables.
Both approaches rely on the analytical solution of an underdetermined quadratic system of rank 2 with 5 variables, producing a family of real solutions, complemented by a short phase of targeted successive trials aimed at achieving integer values that exactly satisfy the equations.
The steps are as follows :
1. We arbitrarily fix 5 small integer values δi (for example, between -3 and 3) such that ∑i[δi] = 0 with δi = ci - di
2. We set xi = mi2 with mi = (ci + di)/2 corresponding to the local center of the variables ci and di, which induces : xi # ci2 # di2 # ci di
where the symbol "#" means "very little different"
3. Given the identities : (c3 - d3) = (c - d)(c2 + c d + d2) and (c5 - d5) = (c - d)(c4 + c3 d + c2 d2 + c d3 + d4), equations S2b become :
    ∑ici - ∑idi = ∑i[δi] = 0
    (∑ici3 - ∑idi3 # 3 ∑i[δi xi]) = 0
    (∑ici5 - ∑idi5 # 5 ∑i[δi xi2]) = 0
4. Using one of the methods mentioned above, we solve the following quadratic system :
(50)     (∑i[δi xi] = 0) and (∑i[δi xi2] = 0)
which gives a family of real solutions for xi.
Solution by elimination of variables :
We fix 3 free variables, for example x1, x2 and x3
We then eliminate x4 between the two equations, which gives an equation of the form : A x52 + B x5 + C = 0, where A, B, and C are explicit quadratic polynomials in x1, x2 and x3, as follows :
    A = δ5 (δ4 + δ5)
    B = 2 δ5 P
    C = P2 + δ4 Q
with P = ∑i=1,3[δi mi2] and Q = ∑i=1,3[δi mi4]
We find the real solutions x5 = [-B ± √(B2 - 4 A C)]/(2 A) and x4 obtained from the equation (∑i[δi xi] = 0).
5. We look for xi close to the square of an integer or a half-integer, which gives ci = √xi + δi/2 and di = √xi - δi/2
6. We substitute the integer solutions ci and di into the exact equations (32) for verification.
7. If the initial result is not verified, further tests are performed by modifying the parameters at two possible levels :
- Exploration of the 3 free parameters xi.
- Selection of the deviation vector δi.
It is highly probable that Maurice Dagbert himself obtained the basic lists (32) using this simple method.

Example of a complete calculation using the variable elimination method :
For example, we fix the first three numbers ci to 1, 7, and 15, and their corresponding values di to 0, 10, and 12.
This is equivalent to fixing the first three values of δi and xi.
We also set (first attempt) the values of δ4 = -2 and δ5 = 1.
We then seek to calculate the last two numbers c4 and c5, and their corresponding values di and di.
The calculations give : P = 330.25, Q = 83985.06, A = -1, B = 2 P, C = P2 - 2 Q, (B2 - 4 A C) = 447.932
Hence :
x5 = 10.312 or 23.542
We retain x5 = 23.542, close to the square of a half-integer (since δ5/2 = 1/2).
c5 = √x5 + δ5/2 = 24.04
d5 = √x5 - δ5/2 = 23.04
x4 = -(δ5 x5 + P)/δ4 = 21.032
We retain x4 = 21.032, close to the square of an integer (since δ4/2 = -1).
c4 = √x4 + δ4/2 = 20.03
d4 = √x4 - δ4/2 = 22.03
We substitute the integer solutions c5 = 24, d5 = 23, c4 = 20, d4 = 22, into the exact equations (32), which are found to be verified on this first trial.

6. Calculation of β1 and β2 from a given N :
Relation (34) is a Diophantine equation that can be written more simply as :
(60)     β1 = 9 u - N and β2 = N - 8 u, with u arbitrary

But three additional constraints must be met :
1. The partial lists of S1 and S2 must be joined to give the illusion of two unique and increasing lists of 17 numbers each.
2. These partial lists must not contain duplicates.
Given translated lists (31)(32), these two constraints can be written :
    (β2 + Min[L2a*, L2b*]) greater than and close to (β1 + Max[L1a*, L1b*])
with Min[L2a*, L2b*] = -24 and Max[L1a*, L1b*] = 25
Given relations (60), this can be written :
(61)     u smaller than and close to u max
with u max = (2 N - (Max[L1a*, L1b*] - Min[L2a*, L2b*]))/17 = (2 N - 49)/17
For N = 2139, u max = 248.8
3. All numbers in lists (La) and (Lb) must be greater than zero.
Given the translated lists (31)(32), this can be written :
    β1 + Min[L2a*, L2b*] > 0
Given relation (60), this can be written :
(62)     u > u min
with u min = (N - Min[L2a*, L2b*])/9 = (N + 24)/9
For N = 2139, u min = 240.3
Given conditions (61)(62), Maurice Dagbert chose 247 for the value of u, resulting in values of 84 and 163 for β1 and β2.

It remains to be ensured that umin < umax for any value of N.
Given conditions (61)(62), this introduces a new constraint :
(63)     N > (9 Max[L1a*, L1b*] - 26 Min[L2a*, L2b*] = 849)
Maurice Dagbert imposed 1000 as the minimum value of N to satisfy this constraint, which then avoids calculating u min.

7. No duplicates in a list or between lists of 17 numbers :
This remarkable property results from three observations :
- By construction, the elementary lists C1 and D1 (see relations (31)) have no duplicates, either internally or between themselves. Therefore, the same is true for the translated lists L1a* and L1b*, given their symmetries, as well as partial listes L1a and L1b.
- Also by construction, the elementary lists C2 and D2 (see relations (32)) have this same property. Therefore, the same is true for the translated lists L2a* and L2b*, given their symmetries, as well as partial listes L2a and L2b.
- By previous choice (see relation (61)), the partial lists L1a and L1b are disjoint from the partial lists L2a and L2b.
Consequently, the two lists of 17 numbers cannot have duplicates, either internally or between themselves, since they result from the simple concatenation of L1a and L2a for the first and of L1b and L2b for the second.

8. Construction of the lists of 17 numbers :
The two lists of 17 numbers provided by Maurice Dagbert are then compiled in four steps :
1. Calculation of u according to relations (61)(62).
2. Calculation of β1 and β2 according to relations (60).
3. Memorization of three lists of gaps based on the gaps between consecutive numbers in each translated list L1a*, L1b*, L2a*, L2b* (see relations (31)(32)) :
List of gaps E1 = [ 4, 5, 14, 4, 14, 5, 4]
List of gaps E2 = [ 4, 5, 8, 6, 11, 2, 10, 1 ]
List of gaps E3 = [ 1, 9, 9, 10, 9, 9, 1 ]
4. Construction of two lists (La) and (Lb) of 17 numbers based on these lists of gaps and the translations β1 and β2, according to the following distribution :
La = [L1a, L2a]
Lb = [L1b, L2b]
with :
L1a = [ (β1 - 25), +E1 ] composed of 8 terms
L2a = [ (β2 - 24), +E2 ] composed of 9 terms
L1b = [ (β1 - 24), +E3 ] composed of 8 terms
L2b = [ (β2 - 23), +E2! ] composed of 9 terms
The symbol "!" means that the list must be read in reverse.

Note : There is another (more complicated) way to construct the two lists of 17 numbers, based on memorizing the elementary lists C1, D1, C2, D2 (see relations (31)(32)) :
L1a = [ (β1 - C1!)4, (β1 + C1)4 ]
L2a = [ (β2 - C2!)5, (β2 + D2 )4 ]
L1b = [ (β1 - D1!)4, (β1 + D1)4 ]
L2b = [ (β2 - D2 !)4, (β2 + C2)5 ]
The symbol "!" means that the list must be read in reverse.
The symbol " " means that the fictitious term 0 in the list should be ignored.
The subscript at the bottom indicates, as a reminder, the number of terms in the quantity within the parentheses.

No duplicates in a list or between lists of 17 numbers :
This remarkable property results from three observations :
- By construction, the basic lists C1 and D1 have no duplicates, either internally or between themselves. Therefore, the same is true for the translated lists L1a* and L1b*, given their symmetries.
- Also by construction, the basic lists C2 and D2 have this same property. Therefore, the same is true for the translated lists L2a* and L2b*, given their symmetries.
- By deliberate choice, lists L1a and L2a are disjoint from lists L1b and L2b (see condition (50)).
Consequently, the two lists of 17 numbers cannot have any duplicates, either internally or between themselves, since they result from the simple concatenation of L1a and L2a for the first and of L1b and L2b for the second.


B1.6.4. Sources relating to Magic tricks :

[ASH] ashmarlow52, Learn This Viral Battery Trick (Youtube, 01:07).
[CAR1] Carrefour francophone, Cours de Magie avec Magislain - Tour 4 : Evasion (Youtube, 03:16).
[CAR2] Carrefour francophone, Cours de magie avec Magislain - Tour 2 : L'élastique à travers les doigts (Youtube, 03:21).
[EIT] Joseph Eitel, The Handcuff Escape Puzzle.
[GAR] Nasr Garouachi, Cordes - Playlist.
[HAF] Nadjib Haffaf, Echapper à la corde facile - DIDACTICIEL (Youtube, 02:45).
[JER] Jérémie-L'école de la magie, 3 TOURS DE MAGIE AVEC 1 ELASTIQUE (Youtube, 08:20).
[MAGE] MagieExpliquée, Apprenez la Téléportation avec un simple Elastique - Secret Révélé (Youtube, 06:43).
[MIR] Minute Facile, Régis le magicien vous explique son incroyable tour de magie avec une corde (Youtube, 03:50).
[PAU] Paulo magie, apprenez un tour impressionnant avec 2 élastiques (Youtube, 05:26).
[PRA] pratiqueTV, Tour de passe passe avec des piles (Youtube, 01:50).
[SHU1] Chen Shuwen, Non-negative Integer Solutions of a1k + a2k + a3k+ a4k = b1k + b2k + b3k + b4k ( k = 2, 4, 6 ).
[SHU2] Chen Shuwen, On the Generalization of the Prouhet-Tarry-Escott Problem.
[TUT] TUTO MAGIE, ARNAQUE OU MAGIE ? COMMENT GAGNER DE L'ARGENT AVEC 3 CARTES EXPLICATION (Youtube, 06:24).
[VAL] TUTUR VAL, 5 TOURS DE MAGIE AVEC DES ELASTIQUES (Youtube, 07:49).
[WIK1] Problème de Prouhet-Tarry-Escott.




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